| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.59 |
| Score | 0% | 72% |
A triathlon course includes a 500m swim, a 20.1km bike ride, and a 9.0km run. What is the total length of the race course?
| 59.9km | |
| 54.3km | |
| 29.6km | |
| 48.5km |
To add these distances, they must share the same unit so first you need to first convert the swim distance from meters (m) to kilometers (km) before adding it to the bike and run distances which are already in km. To convert 500 meters to kilometers, divide the distance by 1000 to get 0.5km then add the remaining distances:
total distance = swim + bike + run
total distance = 0.5km + 20.1km + 9.0km
total distance = 29.6km
What is -5y7 + y7?
| 6y7 | |
| -4y7 | |
| -4y-14 | |
| -4y49 |
To add or subtract terms with exponents, both the base and the exponent must be the same. In this case they are so add the coefficients and retain the base and exponent:
-5y7 + 1y7
(-5 + 1)y7
-4y7
What is 4z5 x 4z3?
| 8z8 | |
| 16z5 | |
| 8z3 | |
| 16z8 |
To multiply terms with exponents, the base of both exponents must be the same. In this case they are so multiply the coefficients and add the exponents:
4z5 x 4z3
(4 x 4)z(5 + 3)
16z8
How many 9-passenger vans will it take to drive all 55 members of the football team to an away game?
| 6 vans | |
| 12 vans | |
| 7 vans | |
| 3 vans |
Calculate the number of vans needed by dividing the number of people that need transported by the capacity of one van:
vans = \( \frac{55}{9} \) = 6\(\frac{1}{9}\)
So, it will take 6 full vans and one partially full van to transport the entire team making a total of 7 vans.
What is \( \frac{2}{7} \) ÷ \( \frac{4}{5} \)?
| \(\frac{1}{6}\) | |
| \(\frac{5}{14}\) | |
| \(\frac{4}{35}\) | |
| \(\frac{4}{21}\) |
To divide fractions, invert the second fraction and then multiply:
\( \frac{2}{7} \) ÷ \( \frac{4}{5} \) = \( \frac{2}{7} \) x \( \frac{5}{4} \)
To multiply fractions, multiply the numerators together and then multiply the denominators together:
\( \frac{2}{7} \) x \( \frac{5}{4} \) = \( \frac{2 x 5}{7 x 4} \) = \( \frac{10}{28} \) = \(\frac{5}{14}\)