| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.98 |
| Score | 0% | 60% |
On average, the center for a basketball team hits 40% of his shots while a guard on the same team hits 50% of his shots. If the guard takes 10 shots during a game, how many shots will the center have to take to score as many points as the guard assuming each shot is worth the same number of points?
| 16 | |
| 9 | |
| 13 | |
| 19 |
guard shots made = shots taken x \( \frac{\text{% made}}{100} \) = 10 x \( \frac{50}{100} \) = \( \frac{50 x 10}{100} \) = \( \frac{500}{100} \) = 5 shots
The center makes 40% of his shots so he'll have to take:
shots made = shots taken x \( \frac{\text{% made}}{100} \)
shots taken = \( \frac{\text{shots taken}}{\frac{\text{% made}}{100}} \)
to make as many shots as the guard. Plugging in values for the center gives us:
center shots taken = \( \frac{5}{\frac{40}{100}} \) = 5 x \( \frac{100}{40} \) = \( \frac{5 x 100}{40} \) = \( \frac{500}{40} \) = 13 shots
to make the same number of shots as the guard and thus score the same number of points.
A tiger in a zoo has consumed 91 pounds of food in 7 days. If the tiger continues to eat at the same rate, in how many more days will its total food consumtion be 182 pounds?
| 6 | |
| 4 | |
| 9 | |
| 7 |
If the tiger has consumed 91 pounds of food in 7 days that's \( \frac{91}{7} \) = 13 pounds of food per day. The tiger needs to consume 182 - 91 = 91 more pounds of food to reach 182 pounds total. At 13 pounds of food per day that's \( \frac{91}{13} \) = 7 more days.
What is \( \frac{4}{6} \) ÷ \( \frac{1}{5} \)?
| 20 | |
| \(\frac{4}{45}\) | |
| 3\(\frac{1}{3}\) | |
| \(\frac{1}{9}\) |
To divide fractions, invert the second fraction and then multiply:
\( \frac{4}{6} \) ÷ \( \frac{1}{5} \) = \( \frac{4}{6} \) x \( \frac{5}{1} \)
To multiply fractions, multiply the numerators together and then multiply the denominators together:
\( \frac{4}{6} \) x \( \frac{5}{1} \) = \( \frac{4 x 5}{6 x 1} \) = \( \frac{20}{6} \) = 3\(\frac{1}{3}\)
What is the least common multiple of 5 and 7?
| 27 | |
| 17 | |
| 23 | |
| 35 |
The first few multiples of 5 are [5, 10, 15, 20, 25, 30, 35, 40, 45, 50] and the first few multiples of 7 are [7, 14, 21, 28, 35, 42, 49, 56, 63, 70]. The first few multiples they share are [35, 70] making 35 the smallest multiple 5 and 7 have in common.
A menswear store is having a sale: "Buy one shirt at full price and get another shirt for 20% off." If Roger buys two shirts, each with a regular price of $37, how much will he pay for both shirts?
| $7.40 | |
| $55.50 | |
| $49.95 | |
| $66.60 |
By buying two shirts, Roger will save $37 x \( \frac{20}{100} \) = \( \frac{$37 x 20}{100} \) = \( \frac{$740}{100} \) = $7.40 on the second shirt.
So, his total cost will be
$37.00 + ($37.00 - $7.40)
$37.00 + $29.60
$66.60