ASVAB Arithmetic Reasoning Practice Test 4739 Results

Your Results Global Average
Questions 5 5
Correct 0 3.05
Score 0% 61%

Review

1

If a rectangle is twice as long as it is wide and has a perimeter of 24 meters, what is the area of the rectangle?

47% Answer Correctly
162 m2
98 m2
32 m2
50 m2

Solution

The area of a rectangle is width (w) x height (h). In this problem we know that the rectangle is twice as long as it is wide so h = 2w. The perimeter of a rectangle is 2w + 2h and we know that the perimeter of this rectangle is 24 meters so the equation becomes: 2w + 2h = 24.

Putting these two equations together and solving for width (w):

2w + 2h = 24
w + h = \( \frac{24}{2} \)
w + h = 12
w = 12 - h

From the question we know that h = 2w so substituting 2w for h gives us:

w = 12 - 2w
3w = 12
w = \( \frac{12}{3} \)
w = 4

Since h = 2w that makes h = (2 x 4) = 8 and the area = h x w = 4 x 8 = 32 m2


2

Simplify \( \frac{40}{44} \).

77% Answer Correctly
\( \frac{2}{5} \)
\( \frac{1}{4} \)
\( \frac{6}{19} \)
\( \frac{10}{11} \)

Solution

To simplify this fraction, first find the greatest common factor between them. The factors of 40 are [1, 2, 4, 5, 8, 10, 20, 40] and the factors of 44 are [1, 2, 4, 11, 22, 44]. They share 3 factors [1, 2, 4] making 4 their greatest common factor (GCF).

Next, divide both numerator and denominator by the GCF:

\( \frac{40}{44} \) = \( \frac{\frac{40}{4}}{\frac{44}{4}} \) = \( \frac{10}{11} \)


3

If the ratio of home fans to visiting fans in a crowd is 3:1 and all 38,000 seats in a stadium are filled, how many home fans are in attendance?

50% Answer Correctly
35,833
26,400
33,333
28,500

Solution

A ratio of 3:1 means that there are 3 home fans for every one visiting fan. So, of every 4 fans, 3 are home fans and \( \frac{3}{4} \) of every fan in the stadium is a home fan:

38,000 fans x \( \frac{3}{4} \) = \( \frac{114000}{4} \) = 28,500 fans.


4

If \( \left|c - 9\right| \) - 7 = 7, which of these is a possible value for c?

62% Answer Correctly
6
0
4
23

Solution

First, solve for \( \left|c - 9\right| \):

\( \left|c - 9\right| \) - 7 = 7
\( \left|c - 9\right| \) = 7 + 7
\( \left|c - 9\right| \) = 14

The value inside the absolute value brackets can be either positive or negative so (c - 9) must equal + 14 or -14 for \( \left|c - 9\right| \) to equal 14:

c - 9 = 14
c = 14 + 9
c = 23
c - 9 = -14
c = -14 + 9
c = -5

So, c = -5 or c = 23.


5

Convert c-5 to remove the negative exponent.

67% Answer Correctly
\( \frac{-1}{c^{-5}} \)
\( \frac{1}{c^{-5}} \)
\( \frac{-5}{c} \)
\( \frac{1}{c^5} \)

Solution

To convert a negative exponent to a positive exponent, calculate the positive exponent then take the reciprocal.