| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.64 |
| Score | 0% | 53% |
Cooks are needed to prepare for a large party. Each cook can bake either 2 large cakes or 17 small cakes per hour. The kitchen is available for 3 hours and 25 large cakes and 390 small cakes need to be baked.
How many cooks are required to bake the required number of cakes during the time the kitchen is available?
| 13 | |
| 5 | |
| 11 | |
| 6 |
If a single cook can bake 2 large cakes per hour and the kitchen is available for 3 hours, a single cook can bake 2 x 3 = 6 large cakes during that time. 25 large cakes are needed for the party so \( \frac{25}{6} \) = 4\(\frac{1}{6}\) cooks are needed to bake the required number of large cakes.
If a single cook can bake 17 small cakes per hour and the kitchen is available for 3 hours, a single cook can bake 17 x 3 = 51 small cakes during that time. 390 small cakes are needed for the party so \( \frac{390}{51} \) = 7\(\frac{11}{17}\) cooks are needed to bake the required number of small cakes.
Because you can't employ a fractional cook, round the number of cooks needed for each type of cake up to the next whole number resulting in 5 + 8 = 13 cooks.
A menswear store is having a sale: "Buy one shirt at full price and get another shirt for 50% off." If Bob buys two shirts, each with a regular price of $21, how much will he pay for both shirts?
| $10.50 | |
| $29.40 | |
| $31.50 | |
| $25.20 |
By buying two shirts, Bob will save $21 x \( \frac{50}{100} \) = \( \frac{$21 x 50}{100} \) = \( \frac{$1050}{100} \) = $10.50 on the second shirt.
So, his total cost will be
$21.00 + ($21.00 - $10.50)
$21.00 + $10.50
$31.50
If the ratio of home fans to visiting fans in a crowd is 5:1 and all 38,000 seats in a stadium are filled, how many home fans are in attendance?
| 31,667 | |
| 27,333 | |
| 24,750 | |
| 21,333 |
A ratio of 5:1 means that there are 5 home fans for every one visiting fan. So, of every 6 fans, 5 are home fans and \( \frac{5}{6} \) of every fan in the stadium is a home fan:
38,000 fans x \( \frac{5}{6} \) = \( \frac{190000}{6} \) = 31,667 fans.
Betty scored 97% on her final exam. If each question was worth 3 points and there were 270 possible points on the exam, how many questions did Betty answer correctly?
| 101 | |
| 84 | |
| 87 | |
| 94 |
Betty scored 97% on the test meaning she earned 97% of the possible points on the test. There were 270 possible points on the test so she earned 270 x 0.97 = 261 points. Each question is worth 3 points so she got \( \frac{261}{3} \) = 87 questions right.
What is \( \frac{3}{9} \) + \( \frac{6}{15} \)?
| 2 \( \frac{5}{45} \) | |
| 2 \( \frac{9}{45} \) | |
| \( \frac{4}{10} \) | |
| \(\frac{11}{15}\) |
To add these fractions, first find the lowest common multiple of their denominators. The first few multiples of 9 are [9, 18, 27, 36, 45, 54, 63, 72, 81, 90] and the first few multiples of 15 are [15, 30, 45, 60, 75, 90]. The first few multiples they share are [45, 90] making 45 the smallest multiple 9 and 15 share.
Next, convert the fractions so each denominator equals the lowest common multiple:
\( \frac{3 x 5}{9 x 5} \) + \( \frac{6 x 3}{15 x 3} \)
\( \frac{15}{45} \) + \( \frac{18}{45} \)
Now, because the fractions share a common denominator, you can add them:
\( \frac{15 + 18}{45} \) = \( \frac{33}{45} \) = \(\frac{11}{15}\)