To divide terms with radicals, divide the coefficients and radicands separately:

\( \frac{28\sqrt{14}}{4\sqrt{2}} \)
\( \frac{28}{4} \) \( \sqrt{\frac{14}{2}} \)
7 \( \sqrt{7} \)

To add these radicals together their radicands must be the same:

5\( \sqrt{125} \) + 6\( \sqrt{5} \)
5\( \sqrt{25 \times 5} \) + 6\( \sqrt{5} \)
5\( \sqrt{5^2 \times 5} \) + 6\( \sqrt{5} \)
(5)(5)\( \sqrt{5} \) + 6\( \sqrt{5} \)
25\( \sqrt{5} \) + 6\( \sqrt{5} \)

Now that the radicands are identical, you can add them together:

To divide terms with exponents, the base of both exponents must be the same. In this case they are so divide the coefficients and subtract the exponents:

\( \frac{-8b^7}{2b^3} \)
\( \frac{-8}{2} \) b^{(7 - 3)}
-4b⁴

Use PEMDAS (Parentheses, Exponents, Multipy/Divide, Add/Subtract):

5 + (4 + 3) ÷ 5 x 4 - 2²
P: 5 + (7) ÷ 5 x 4 - 2²
E: 5 + 7 ÷ 5 x 4 - 4
MD: 5 + \( \frac{7}{5} \) x 4 - 4
MD: 5 + \( \frac{28}{5} \) - 4
AS: \( \frac{25}{5} \) + \( \frac{28}{5} \) - 4
AS: \( \frac{53}{5} \) - 4
AS: \( \frac{53 - 20}{5} \)
\( \frac{33}{5} \)
6\(\frac{3}{5}\)

The yearly interest charged on this loan is the annual interest rate multiplied by the amount borrowed:

interest = annual interest rate x loan amount

i = (\( \frac{6}{100} \)) x $1,000
i = 0.03 x $1,000

No payments were made so the total amount due is the original amount + the accumulated interest: