Use PEMDAS (Parentheses, Exponents, Multipy/Divide, Add/Subtract):

2 + (4 + 4) ÷ 5 x 4 - 5²
P: 2 + (8) ÷ 5 x 4 - 5²
E: 2 + 8 ÷ 5 x 4 - 25
MD: 2 + \( \frac{8}{5} \) x 4 - 25
MD: 2 + \( \frac{32}{5} \) - 25
AS: \( \frac{10}{5} \) + \( \frac{32}{5} \) - 25
AS: \( \frac{42}{5} \) - 25
AS: \( \frac{42 - 125}{5} \)
\( \frac{-83}{5} \)
-16\(\frac{3}{5}\)

The number of students taking German or Spanish is 9 + 12 = 21. Of that group of 21, 7 are taking both languages so they've been counted twice (once in the German group and once in the Spanish group). Subtracting them out leaves 21 - 7 = 14 who are taking at least one language. 23 - 14 = 9 students who are not taking either language.

If the tiger has consumed 90 pounds of food in 10 days that's \( \frac{90}{10} \) = 9 pounds of food per day. The tiger needs to consume 135 - 90 = 45 more pounds of food to reach 135 pounds total. At 9 pounds of food per day that's \( \frac{45}{9} \) = 5 more days.

To multiply terms with exponents, the base of both exponents must be the same. In this case they are so multiply the coefficients and add the exponents:

9x⁴ x 3x³
(9 x 3)x^{(4 + 3)}
27x⁷

The factors of 24 are [1, 2, 3, 4, 6, 8, 12, 24] and the factors of 32 are [1, 2, 4, 8, 16, 32]. They share 4 factors [1, 2, 4, 8] making 8 the greatest factor 24 and 32 have in common.