| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.50 |
| Score | 0% | 70% |
A bread recipe calls for 2 cups of flour. If you only have 1 cup, how much more flour is needed?
| 2\(\frac{3}{8}\) cups | |
| 1 cups | |
| 2\(\frac{1}{8}\) cups | |
| 3 cups |
The amount of flour you need is (2 - 1) cups. Rewrite the quantities so they share a common denominator and subtract:
(\( \frac{16}{8} \) - \( \frac{8}{8} \)) cups
\( \frac{8}{8} \) cups
1 cups
What is \( \frac{7}{6} \) + \( \frac{7}{10} \)?
| 1 \( \frac{6}{30} \) | |
| \( \frac{8}{14} \) | |
| 1\(\frac{13}{15}\) | |
| 1 \( \frac{9}{13} \) |
To add these fractions, first find the lowest common multiple of their denominators. The first few multiples of 6 are [6, 12, 18, 24, 30, 36, 42, 48, 54, 60] and the first few multiples of 10 are [10, 20, 30, 40, 50, 60, 70, 80, 90]. The first few multiples they share are [30, 60, 90] making 30 the smallest multiple 6 and 10 share.
Next, convert the fractions so each denominator equals the lowest common multiple:
\( \frac{7 x 5}{6 x 5} \) + \( \frac{7 x 3}{10 x 3} \)
\( \frac{35}{30} \) + \( \frac{21}{30} \)
Now, because the fractions share a common denominator, you can add them:
\( \frac{35 + 21}{30} \) = \( \frac{56}{30} \) = 1\(\frac{13}{15}\)
What is the distance in miles of a trip that takes 7 hours at an average speed of 60 miles per hour?
| 420 miles | |
| 75 miles | |
| 160 miles | |
| 30 miles |
Average speed in miles per hour is the number of miles traveled divided by the number of hours:
speed = \( \frac{\text{distance}}{\text{time}} \)Solving for distance:
distance = \( \text{speed} \times \text{time} \)
distance = \( 60mph \times 7h \)
420 miles
What is (a4)2?
| 2a4 | |
| a6 | |
| a8 | |
| 4a2 |
To raise a term with an exponent to another exponent, retain the base and multiply the exponents:
(a4)2In a class of 19 students, 10 are taking German and 7 are taking Spanish. Of the students studying German or Spanish, 3 are taking both courses. How many students are not enrolled in either course?
| 17 | |
| 5 | |
| 18 | |
| 12 |
The number of students taking German or Spanish is 10 + 7 = 17. Of that group of 17, 3 are taking both languages so they've been counted twice (once in the German group and once in the Spanish group). Subtracting them out leaves 17 - 3 = 14 who are taking at least one language. 19 - 14 = 5 students who are not taking either language.