ASVAB Arithmetic Reasoning Practice Test 482646 Results

Your Results Global Average
Questions 5 5
Correct 0 3.12
Score 0% 62%

Review

1

What is -5a2 x 9a3?

75% Answer Correctly
4a5
4a3
4a6
-45a5

Solution

To multiply terms with exponents, the base of both exponents must be the same. In this case they are so multiply the coefficients and add the exponents:

-5a2 x 9a3
(-5 x 9)a(2 + 3)
-45a5


2

What is the next number in this sequence: 1, 8, 15, 22, 29, __________ ?

92% Answer Correctly
32
33
37
36

Solution

The equation for this sequence is:

an = an-1 + 7

where n is the term's order in the sequence, an is the value of the term, and an-1 is the value of the term before an. This makes the next number:

a6 = a5 + 7
a6 = 29 + 7
a6 = 36


3

On average, the center for a basketball team hits 50% of his shots while a guard on the same team hits 70% of his shots. If the guard takes 25 shots during a game, how many shots will the center have to take to score as many points as the guard assuming each shot is worth the same number of points?

42% Answer Correctly
31
34
32
49

Solution
If the guard hits 70% of his shots and takes 25 shots he'll make:

guard shots made = shots taken x \( \frac{\text{% made}}{100} \) = 25 x \( \frac{70}{100} \) = \( \frac{70 x 25}{100} \) = \( \frac{1750}{100} \) = 17 shots

The center makes 50% of his shots so he'll have to take:

shots made = shots taken x \( \frac{\text{% made}}{100} \)
shots taken = \( \frac{\text{shots taken}}{\frac{\text{% made}}{100}} \)

to make as many shots as the guard. Plugging in values for the center gives us:

center shots taken = \( \frac{17}{\frac{50}{100}} \) = 17 x \( \frac{100}{50} \) = \( \frac{17 x 100}{50} \) = \( \frac{1700}{50} \) = 34 shots

to make the same number of shots as the guard and thus score the same number of points.


4

Convert c-2 to remove the negative exponent.

67% Answer Correctly
\( \frac{-2}{-c} \)
\( \frac{-2}{c} \)
\( \frac{1}{c^{-2}} \)
\( \frac{1}{c^2} \)

Solution

To convert a negative exponent to a positive exponent, calculate the positive exponent then take the reciprocal.


5

What is \( 7 \)\( \sqrt{45} \) + \( 9 \)\( \sqrt{5} \)

35% Answer Correctly
30\( \sqrt{5} \)
16\( \sqrt{45} \)
16\( \sqrt{225} \)
63\( \sqrt{45} \)

Solution

To add these radicals together their radicands must be the same:

7\( \sqrt{45} \) + 9\( \sqrt{5} \)
7\( \sqrt{9 \times 5} \) + 9\( \sqrt{5} \)
7\( \sqrt{3^2 \times 5} \) + 9\( \sqrt{5} \)
(7)(3)\( \sqrt{5} \) + 9\( \sqrt{5} \)
21\( \sqrt{5} \) + 9\( \sqrt{5} \)

Now that the radicands are identical, you can add them together:

21\( \sqrt{5} \) + 9\( \sqrt{5} \)
(21 + 9)\( \sqrt{5} \)
30\( \sqrt{5} \)