| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.12 |
| Score | 0% | 62% |
What is -5a2 x 9a3?
| 4a5 | |
| 4a3 | |
| 4a6 | |
| -45a5 |
To multiply terms with exponents, the base of both exponents must be the same. In this case they are so multiply the coefficients and add the exponents:
-5a2 x 9a3
(-5 x 9)a(2 + 3)
-45a5
What is the next number in this sequence: 1, 8, 15, 22, 29, __________ ?
| 32 | |
| 33 | |
| 37 | |
| 36 |
The equation for this sequence is:
an = an-1 + 7
where n is the term's order in the sequence, an is the value of the term, and an-1 is the value of the term before an. This makes the next number:
a6 = a5 + 7
a6 = 29 + 7
a6 = 36
On average, the center for a basketball team hits 50% of his shots while a guard on the same team hits 70% of his shots. If the guard takes 25 shots during a game, how many shots will the center have to take to score as many points as the guard assuming each shot is worth the same number of points?
| 31 | |
| 34 | |
| 32 | |
| 49 |
guard shots made = shots taken x \( \frac{\text{% made}}{100} \) = 25 x \( \frac{70}{100} \) = \( \frac{70 x 25}{100} \) = \( \frac{1750}{100} \) = 17 shots
The center makes 50% of his shots so he'll have to take:
shots made = shots taken x \( \frac{\text{% made}}{100} \)
shots taken = \( \frac{\text{shots taken}}{\frac{\text{% made}}{100}} \)
to make as many shots as the guard. Plugging in values for the center gives us:
center shots taken = \( \frac{17}{\frac{50}{100}} \) = 17 x \( \frac{100}{50} \) = \( \frac{17 x 100}{50} \) = \( \frac{1700}{50} \) = 34 shots
to make the same number of shots as the guard and thus score the same number of points.
Convert c-2 to remove the negative exponent.
| \( \frac{-2}{-c} \) | |
| \( \frac{-2}{c} \) | |
| \( \frac{1}{c^{-2}} \) | |
| \( \frac{1}{c^2} \) |
To convert a negative exponent to a positive exponent, calculate the positive exponent then take the reciprocal.
What is \( 7 \)\( \sqrt{45} \) + \( 9 \)\( \sqrt{5} \)
| 30\( \sqrt{5} \) | |
| 16\( \sqrt{45} \) | |
| 16\( \sqrt{225} \) | |
| 63\( \sqrt{45} \) |
To add these radicals together their radicands must be the same:
7\( \sqrt{45} \) + 9\( \sqrt{5} \)
7\( \sqrt{9 \times 5} \) + 9\( \sqrt{5} \)
7\( \sqrt{3^2 \times 5} \) + 9\( \sqrt{5} \)
(7)(3)\( \sqrt{5} \) + 9\( \sqrt{5} \)
21\( \sqrt{5} \) + 9\( \sqrt{5} \)
Now that the radicands are identical, you can add them together:
21\( \sqrt{5} \) + 9\( \sqrt{5} \)