| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.41 |
| Score | 0% | 68% |
A factor is a positive __________ that divides evenly into a given number.
mixed number |
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improper fraction |
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fraction |
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integer |
A factor is a positive integer that divides evenly into a given number. For example, the factors of 8 are 1, 2, 4, and 8.
Roger loaned April $900 at an annual interest rate of 1%. If no payments are made, what is the total amount owed at the end of the first year?
| $909 | |
| $918 | |
| $981 | |
| $972 |
The yearly interest charged on this loan is the annual interest rate multiplied by the amount borrowed:
interest = annual interest rate x loan amount
i = (\( \frac{6}{100} \)) x $900
i = 0.01 x $900
No payments were made so the total amount due is the original amount + the accumulated interest:
total = $900 + $9What is 8z2 x 4z6?
| 32z2 | |
| 12z2 | |
| 32z8 | |
| 12z8 |
To multiply terms with exponents, the base of both exponents must be the same. In this case they are so multiply the coefficients and add the exponents:
8z2 x 4z6
(8 x 4)z(2 + 6)
32z8
If all of a roofing company's 12 workers are required to staff 3 roofing crews, how many workers need to be added during the busy season in order to send 5 complete crews out on jobs?
| 8 | |
| 18 | |
| 3 | |
| 6 |
In order to find how many additional workers are needed to staff the extra crews you first need to calculate how many workers are on a crew. There are 12 workers at the company now and that's enough to staff 3 crews so there are \( \frac{12}{3} \) = 4 workers on a crew. 5 crews are needed for the busy season which, at 4 workers per crew, means that the roofing company will need 5 x 4 = 20 total workers to staff the crews during the busy season. The company already employs 12 workers so they need to add 20 - 12 = 8 new staff for the busy season.
What is \( \frac{9}{2} \) - \( \frac{4}{6} \)?
| 3\(\frac{5}{6}\) | |
| 1 \( \frac{9}{6} \) | |
| \( \frac{8}{6} \) | |
| 2 \( \frac{1}{6} \) |
To subtract these fractions, first find the lowest common multiple of their denominators. The first few multiples of 2 are [2, 4, 6, 8, 10, 12, 14, 16, 18, 20] and the first few multiples of 6 are [6, 12, 18, 24, 30, 36, 42, 48, 54, 60]. The first few multiples they share are [6, 12, 18, 24, 30] making 6 the smallest multiple 2 and 6 share.
Next, convert the fractions so each denominator equals the lowest common multiple:
\( \frac{9 x 3}{2 x 3} \) - \( \frac{4 x 1}{6 x 1} \)
\( \frac{27}{6} \) - \( \frac{4}{6} \)
Now, because the fractions share a common denominator, you can subtract them:
\( \frac{27 - 4}{6} \) = \( \frac{23}{6} \) = 3\(\frac{5}{6}\)