ASVAB Arithmetic Reasoning Practice Test 483050 Results

Your Results Global Average
Questions 5 5
Correct 0 3.41
Score 0% 68%

Review

1

A factor is a positive __________ that divides evenly into a given number.

78% Answer Correctly

mixed number

improper fraction

fraction

integer


Solution

A factor is a positive integer that divides evenly into a given number. For example, the factors of 8 are 1, 2, 4, and 8.


2

Roger loaned April $900 at an annual interest rate of 1%. If no payments are made, what is the total amount owed at the end of the first year?

71% Answer Correctly
$909
$918
$981
$972

Solution

The yearly interest charged on this loan is the annual interest rate multiplied by the amount borrowed:

interest = annual interest rate x loan amount

i = (\( \frac{6}{100} \)) x $900
i = 0.01 x $900

No payments were made so the total amount due is the original amount + the accumulated interest:

total = $900 + $9
total = $909


3

What is 8z2 x 4z6?

75% Answer Correctly
32z2
12z2
32z8
12z8

Solution

To multiply terms with exponents, the base of both exponents must be the same. In this case they are so multiply the coefficients and add the exponents:

8z2 x 4z6
(8 x 4)z(2 + 6)
32z8


4

If all of a roofing company's 12 workers are required to staff 3 roofing crews, how many workers need to be added during the busy season in order to send 5 complete crews out on jobs?

55% Answer Correctly
8
18
3
6

Solution

In order to find how many additional workers are needed to staff the extra crews you first need to calculate how many workers are on a crew. There are 12 workers at the company now and that's enough to staff 3 crews so there are \( \frac{12}{3} \) = 4 workers on a crew. 5 crews are needed for the busy season which, at 4 workers per crew, means that the roofing company will need 5 x 4 = 20 total workers to staff the crews during the busy season. The company already employs 12 workers so they need to add 20 - 12 = 8 new staff for the busy season.


5

What is \( \frac{9}{2} \) - \( \frac{4}{6} \)?

61% Answer Correctly
3\(\frac{5}{6}\)
1 \( \frac{9}{6} \)
\( \frac{8}{6} \)
2 \( \frac{1}{6} \)

Solution

To subtract these fractions, first find the lowest common multiple of their denominators. The first few multiples of 2 are [2, 4, 6, 8, 10, 12, 14, 16, 18, 20] and the first few multiples of 6 are [6, 12, 18, 24, 30, 36, 42, 48, 54, 60]. The first few multiples they share are [6, 12, 18, 24, 30] making 6 the smallest multiple 2 and 6 share.

Next, convert the fractions so each denominator equals the lowest common multiple:

\( \frac{9 x 3}{2 x 3} \) - \( \frac{4 x 1}{6 x 1} \)

\( \frac{27}{6} \) - \( \frac{4}{6} \)

Now, because the fractions share a common denominator, you can subtract them:

\( \frac{27 - 4}{6} \) = \( \frac{23}{6} \) = 3\(\frac{5}{6}\)