guard shots made = shots taken x \( \frac{\text{% made}}{100} \) = 20 x \( \frac{35}{100} \) = \( \frac{35 x 20}{100} \) = \( \frac{700}{100} \) = 7 shots

The center makes 25% of his shots so he'll have to take:

shots made = shots taken x \( \frac{\text{% made}}{100} \)
shots taken = \( \frac{\text{shots taken}}{\frac{\text{% made}}{100}} \)

to make as many shots as the guard. Plugging in values for the center gives us:

center shots taken = \( \frac{7}{\frac{25}{100}} \) = 7 x \( \frac{100}{25} \) = \( \frac{7 x 100}{25} \) = \( \frac{700}{25} \) = 28 shots

to make the same number of shots as the guard and thus score the same number of points.

If the tiger has consumed 104 pounds of food in 8 days that's \( \frac{104}{8} \) = 13 pounds of food per day. The tiger needs to consume 169 - 104 = 65 more pounds of food to reach 169 pounds total. At 13 pounds of food per day that's \( \frac{65}{13} \) = 5 more days.

There are 2 4-passenger taxis available so that's 2 x 4 = 8 total seats. There are 9 people needing transportation leaving 9 - 8 = 1 who will have to find other transportation.

A factorial is the product of an integer and all the positive integers below it. To solve a fraction featuring factorials, expand the factorials and cancel out like numbers:

\( \frac{6!}{3!} \)
\( \frac{6 \times 5 \times 4 \times 3 \times 2 \times 1}{3 \times 2 \times 1} \)
\( \frac{6 \times 5 \times 4}{1} \)
\( 6 \times 5 \times 4 \)
120

The distributive property for division helps in solving expressions like \({b + c \over a}\). It specifies that the result of dividing a fraction with multiple terms in the numerator and one term in the denominator can be obtained by dividing each term individually and then totaling the results: \({b + c \over a} = {b \over a} + {c \over a}\). For example, \({a^3 + 6a^2 \over a^2} = {a^3 \over a^2} + {6a^2 \over a^2} = a + 6\).