| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.36 |
| Score | 0% | 67% |
How many 7-passenger vans will it take to drive all 82 members of the football team to an away game?
| 8 vans | |
| 4 vans | |
| 15 vans | |
| 12 vans |
Calculate the number of vans needed by dividing the number of people that need transported by the capacity of one van:
vans = \( \frac{82}{7} \) = 11\(\frac{5}{7}\)
So, it will take 11 full vans and one partially full van to transport the entire team making a total of 12 vans.
What is the next number in this sequence: 1, 5, 13, 25, 41, __________ ?
| 53 | |
| 61 | |
| 62 | |
| 55 |
The equation for this sequence is:
an = an-1 + 4(n - 1)
where n is the term's order in the sequence, an is the value of the term, and an-1 is the value of the term before an. This makes the next number:
a6 = a5 + 4(6 - 1)
a6 = 41 + 4(5)
a6 = 61
Which of the following is an improper fraction?
\({a \over 5} \) |
|
\({2 \over 5} \) |
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\(1 {2 \over 5} \) |
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\({7 \over 5} \) |
A rational number (or fraction) is represented as a ratio between two integers, a and b, and has the form \({a \over b}\) where a is the numerator and b is the denominator. An improper fraction (\({5 \over 3} \)) has a numerator with a greater absolute value than the denominator and can be converted into a mixed number (\(1 {2 \over 3} \)) which has a whole number part and a fractional part.
The __________ is the smallest positive integer that is a multiple of two or more integers.
absolute value |
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greatest common factor |
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least common factor |
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least common multiple |
The least common multiple (LCM) is the smallest positive integer that is a multiple of two or more integers.
What is \( \frac{8}{6} \) - \( \frac{5}{10} \)?
| \(\frac{5}{6}\) | |
| 2 \( \frac{8}{30} \) | |
| 2 \( \frac{2}{30} \) | |
| 1 \( \frac{8}{15} \) |
To subtract these fractions, first find the lowest common multiple of their denominators. The first few multiples of 6 are [6, 12, 18, 24, 30, 36, 42, 48, 54, 60] and the first few multiples of 10 are [10, 20, 30, 40, 50, 60, 70, 80, 90]. The first few multiples they share are [30, 60, 90] making 30 the smallest multiple 6 and 10 share.
Next, convert the fractions so each denominator equals the lowest common multiple:
\( \frac{8 x 5}{6 x 5} \) - \( \frac{5 x 3}{10 x 3} \)
\( \frac{40}{30} \) - \( \frac{15}{30} \)
Now, because the fractions share a common denominator, you can subtract them:
\( \frac{40 - 15}{30} \) = \( \frac{25}{30} \) = \(\frac{5}{6}\)