ASVAB Arithmetic Reasoning Practice Test 483526 Results

Your Results Global Average
Questions 5 5
Correct 0 2.64
Score 0% 53%

Review

1

How many 2 gallon cans worth of fuel would you need to pour into an empty 12 gallon tank to fill it exactly halfway?

52% Answer Correctly
3
6
9
7

Solution

To fill a 12 gallon tank exactly halfway you'll need 6 gallons of fuel. Each fuel can holds 2 gallons so:

cans = \( \frac{6 \text{ gallons}}{2 \text{ gallons}} \) = 3


2

What is \( \frac{-9z^8}{8z^4} \)?

60% Answer Correctly
-1\(\frac{1}{8}\)z2
-1\(\frac{1}{8}\)z4
-1\(\frac{1}{8}\)z-4
-1\(\frac{1}{8}\)z12

Solution

To divide terms with exponents, the base of both exponents must be the same. In this case they are so divide the coefficients and subtract the exponents:

\( \frac{-9z^8}{8z^4} \)
\( \frac{-9}{8} \) z(8 - 4)
-1\(\frac{1}{8}\)z4


3

What is \( 9 \)\( \sqrt{8} \) + \( 6 \)\( \sqrt{2} \)

35% Answer Correctly
54\( \sqrt{8} \)
54\( \sqrt{2} \)
24\( \sqrt{2} \)
54\( \sqrt{16} \)

Solution

To add these radicals together their radicands must be the same:

9\( \sqrt{8} \) + 6\( \sqrt{2} \)
9\( \sqrt{4 \times 2} \) + 6\( \sqrt{2} \)
9\( \sqrt{2^2 \times 2} \) + 6\( \sqrt{2} \)
(9)(2)\( \sqrt{2} \) + 6\( \sqrt{2} \)
18\( \sqrt{2} \) + 6\( \sqrt{2} \)

Now that the radicands are identical, you can add them together:

18\( \sqrt{2} \) + 6\( \sqrt{2} \)
(18 + 6)\( \sqrt{2} \)
24\( \sqrt{2} \)


4

Find the average of the following numbers: 15, 11, 14, 12.

74% Answer Correctly
9
13
16
17

Solution

To find the average of these 4 numbers add them together then divide by 4:

\( \frac{15 + 11 + 14 + 12}{4} \) = \( \frac{52}{4} \) = 13


5

On average, the center for a basketball team hits 35% of his shots while a guard on the same team hits 55% of his shots. If the guard takes 30 shots during a game, how many shots will the center have to take to score as many points as the guard assuming each shot is worth the same number of points?

42% Answer Correctly
46
48
67
28

Solution
If the guard hits 55% of his shots and takes 30 shots he'll make:

guard shots made = shots taken x \( \frac{\text{% made}}{100} \) = 30 x \( \frac{55}{100} \) = \( \frac{55 x 30}{100} \) = \( \frac{1650}{100} \) = 16 shots

The center makes 35% of his shots so he'll have to take:

shots made = shots taken x \( \frac{\text{% made}}{100} \)
shots taken = \( \frac{\text{shots taken}}{\frac{\text{% made}}{100}} \)

to make as many shots as the guard. Plugging in values for the center gives us:

center shots taken = \( \frac{16}{\frac{35}{100}} \) = 16 x \( \frac{100}{35} \) = \( \frac{16 x 100}{35} \) = \( \frac{1600}{35} \) = 46 shots

to make the same number of shots as the guard and thus score the same number of points.