| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.87 |
| Score | 0% | 77% |
If a car travels 50 miles in 2 hours, what is the average speed?
| 25 mph | |
| 50 mph | |
| 26 | |
| 70 mph |
Average speed in miles per hour is the number of miles traveled divided by the number of hours:
speed = \( \frac{\text{distance}}{\text{time}} \)What is 5c5 x 8c2?
| 13c5 | |
| 40c5 | |
| 40c2 | |
| 40c7 |
To multiply terms with exponents, the base of both exponents must be the same. In this case they are so multiply the coefficients and add the exponents:
5c5 x 8c2
(5 x 8)c(5 + 2)
40c7
Simplify \( \frac{28}{68} \).
| \( \frac{7}{17} \) | |
| \( \frac{7}{18} \) | |
| \( \frac{3}{8} \) | |
| \( \frac{5}{11} \) |
To simplify this fraction, first find the greatest common factor between them. The factors of 28 are [1, 2, 4, 7, 14, 28] and the factors of 68 are [1, 2, 4, 17, 34, 68]. They share 3 factors [1, 2, 4] making 4 their greatest common factor (GCF).
Next, divide both numerator and denominator by the GCF:
\( \frac{28}{68} \) = \( \frac{\frac{28}{4}}{\frac{68}{4}} \) = \( \frac{7}{17} \)
What is the next number in this sequence: 1, 4, 7, 10, 13, __________ ?
| 13 | |
| 10 | |
| 16 | |
| 22 |
The equation for this sequence is:
an = an-1 + 3
where n is the term's order in the sequence, an is the value of the term, and an-1 is the value of the term before an. This makes the next number:
a6 = a5 + 3
a6 = 13 + 3
a6 = 16
A tiger in a zoo has consumed 77 pounds of food in 7 days. If the tiger continues to eat at the same rate, in how many more days will its total food consumtion be 132 pounds?
| 12 | |
| 9 | |
| 8 | |
| 5 |
If the tiger has consumed 77 pounds of food in 7 days that's \( \frac{77}{7} \) = 11 pounds of food per day. The tiger needs to consume 132 - 77 = 55 more pounds of food to reach 132 pounds total. At 11 pounds of food per day that's \( \frac{55}{11} \) = 5 more days.