| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.26 |
| Score | 0% | 65% |
If there were a total of 300 raffle tickets sold and you bought 24 tickets, what's the probability that you'll win the raffle?
| 9% | |
| 1% | |
| 8% | |
| 7% |
You have 24 out of the total of 300 raffle tickets sold so you have a (\( \frac{24}{300} \)) x 100 = \( \frac{24 \times 100}{300} \) = \( \frac{2400}{300} \) = 8% chance to win the raffle.
Which of the following is not a prime number?
9 |
|
5 |
|
7 |
|
2 |
A prime number is an integer greater than 1 that has no factors other than 1 and itself. Examples of prime numbers include 2, 3, 5, 7, and 11.
Which of the following is a mixed number?
\({5 \over 7} \) |
|
\(1 {2 \over 5} \) |
|
\({a \over 5} \) |
|
\({7 \over 5} \) |
A rational number (or fraction) is represented as a ratio between two integers, a and b, and has the form \({a \over b}\) where a is the numerator and b is the denominator. An improper fraction (\({5 \over 3} \)) has a numerator with a greater absolute value than the denominator and can be converted into a mixed number (\(1 {2 \over 3} \)) which has a whole number part and a fractional part.
A menswear store is having a sale: "Buy one shirt at full price and get another shirt for 15% off." If Ezra buys two shirts, each with a regular price of $38, how much money will he save?
| $11.40 | |
| $17.10 | |
| $5.70 | |
| $1.90 |
By buying two shirts, Ezra will save $38 x \( \frac{15}{100} \) = \( \frac{$38 x 15}{100} \) = \( \frac{$570}{100} \) = $5.70 on the second shirt.
If a rectangle is twice as long as it is wide and has a perimeter of 30 meters, what is the area of the rectangle?
| 50 m2 | |
| 162 m2 | |
| 32 m2 | |
| 72 m2 |
The area of a rectangle is width (w) x height (h). In this problem we know that the rectangle is twice as long as it is wide so h = 2w. The perimeter of a rectangle is 2w + 2h and we know that the perimeter of this rectangle is 30 meters so the equation becomes: 2w + 2h = 30.
Putting these two equations together and solving for width (w):
2w + 2h = 30
w + h = \( \frac{30}{2} \)
w + h = 15
w = 15 - h
From the question we know that h = 2w so substituting 2w for h gives us:
w = 15 - 2w
3w = 15
w = \( \frac{15}{3} \)
w = 5
Since h = 2w that makes h = (2 x 5) = 10 and the area = h x w = 5 x 10 = 50 m2