ASVAB Arithmetic Reasoning Practice Test 492703 Results

Your Results Global Average
Questions 5 5
Correct 0 3.26
Score 0% 65%

Review

1

If there were a total of 300 raffle tickets sold and you bought 24 tickets, what's the probability that you'll win the raffle?

60% Answer Correctly
9%
1%
8%
7%

Solution

You have 24 out of the total of 300 raffle tickets sold so you have a (\( \frac{24}{300} \)) x 100 = \( \frac{24 \times 100}{300} \) = \( \frac{2400}{300} \) = 8% chance to win the raffle.


2

Which of the following is not a prime number?

64% Answer Correctly

9

5

7

2


Solution

A prime number is an integer greater than 1 that has no factors other than 1 and itself. Examples of prime numbers include 2, 3, 5, 7, and 11.


3

Which of the following is a mixed number?

82% Answer Correctly

\({5 \over 7} \)

\(1 {2 \over 5} \)

\({a \over 5} \)

\({7 \over 5} \)


Solution

A rational number (or fraction) is represented as a ratio between two integers, a and b, and has the form \({a \over b}\) where a is the numerator and b is the denominator. An improper fraction (\({5 \over 3} \)) has a numerator with a greater absolute value than the denominator and can be converted into a mixed number (\(1 {2 \over 3} \)) which has a whole number part and a fractional part.


4

A menswear store is having a sale: "Buy one shirt at full price and get another shirt for 15% off." If Ezra buys two shirts, each with a regular price of $38, how much money will he save?

70% Answer Correctly
$11.40
$17.10
$5.70
$1.90

Solution

By buying two shirts, Ezra will save $38 x \( \frac{15}{100} \) = \( \frac{$38 x 15}{100} \) = \( \frac{$570}{100} \) = $5.70 on the second shirt.


5

If a rectangle is twice as long as it is wide and has a perimeter of 30 meters, what is the area of the rectangle?

47% Answer Correctly
50 m2
162 m2
32 m2
72 m2

Solution

The area of a rectangle is width (w) x height (h). In this problem we know that the rectangle is twice as long as it is wide so h = 2w. The perimeter of a rectangle is 2w + 2h and we know that the perimeter of this rectangle is 30 meters so the equation becomes: 2w + 2h = 30.

Putting these two equations together and solving for width (w):

2w + 2h = 30
w + h = \( \frac{30}{2} \)
w + h = 15
w = 15 - h

From the question we know that h = 2w so substituting 2w for h gives us:

w = 15 - 2w
3w = 15
w = \( \frac{15}{3} \)
w = 5

Since h = 2w that makes h = (2 x 5) = 10 and the area = h x w = 5 x 10 = 50 m2