| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.29 |
| Score | 0% | 66% |
A triathlon course includes a 500m swim, a 40.9km bike ride, and a 12.5km run. What is the total length of the race course?
| 65.8km | |
| 59.4km | |
| 53.9km | |
| 42.6km |
To add these distances, they must share the same unit so first you need to first convert the swim distance from meters (m) to kilometers (km) before adding it to the bike and run distances which are already in km. To convert 500 meters to kilometers, divide the distance by 1000 to get 0.5km then add the remaining distances:
total distance = swim + bike + run
total distance = 0.5km + 40.9km + 12.5km
total distance = 53.9km
If a car travels 70 miles in 1 hour, what is the average speed?
| 65 mph | |
| 70 mph | |
| 20 mph | |
| 45 mph |
Average speed in miles per hour is the number of miles traveled divided by the number of hours:
speed = \( \frac{\text{distance}}{\text{time}} \)In a class of 25 students, 11 are taking German and 5 are taking Spanish. Of the students studying German or Spanish, 4 are taking both courses. How many students are not enrolled in either course?
| 22 | |
| 10 | |
| 13 | |
| 25 |
The number of students taking German or Spanish is 11 + 5 = 16. Of that group of 16, 4 are taking both languages so they've been counted twice (once in the German group and once in the Spanish group). Subtracting them out leaves 16 - 4 = 12 who are taking at least one language. 25 - 12 = 13 students who are not taking either language.
What is \( \frac{-9z^8}{9z^2} \)?
| -z10 | |
| -z6 | |
| -z16 | |
| -z-6 |
To divide terms with exponents, the base of both exponents must be the same. In this case they are so divide the coefficients and subtract the exponents:
\( \frac{-9z^8}{9z^2} \)
\( \frac{-9}{9} \) z(8 - 2)
-z6
How many 1 gallon cans worth of fuel would you need to pour into an empty 8 gallon tank to fill it exactly halfway?
| 5 | |
| 7 | |
| 9 | |
| 4 |
To fill a 8 gallon tank exactly halfway you'll need 4 gallons of fuel. Each fuel can holds 1 gallons so:
cans = \( \frac{4 \text{ gallons}}{1 \text{ gallons}} \) = 4