| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.01 |
| Score | 0% | 60% |
How many 1\(\frac{1}{2}\) gallon cans worth of fuel would you need to pour into an empty 15 gallon tank to fill it exactly halfway?
| 8 | |
| 10 | |
| 4 | |
| 5 |
To fill a 15 gallon tank exactly halfway you'll need 7\(\frac{1}{2}\) gallons of fuel. Each fuel can holds 1\(\frac{1}{2}\) gallons so:
cans = \( \frac{7\frac{1}{2} \text{ gallons}}{1\frac{1}{2} \text{ gallons}} \) = 5
A circular logo is enlarged to fit the lid of a jar. The new diameter is 45% larger than the original. By what percentage has the area of the logo increased?
| 15% | |
| 20% | |
| 22\(\frac{1}{2}\)% | |
| 32\(\frac{1}{2}\)% |
The area of a circle is given by the formula A = πr2 where r is the radius of the circle. The radius of a circle is its diameter divided by two so A = π(\( \frac{d}{2} \))2. If the diameter of the logo increases by 45% the radius (and, consequently, the total area) increases by \( \frac{45\text{%}}{2} \) = 22\(\frac{1}{2}\)%
A tiger in a zoo has consumed 28 pounds of food in 4 days. If the tiger continues to eat at the same rate, in how many more days will its total food consumtion be 77 pounds?
| 9 | |
| 5 | |
| 6 | |
| 7 |
If the tiger has consumed 28 pounds of food in 4 days that's \( \frac{28}{4} \) = 7 pounds of food per day. The tiger needs to consume 77 - 28 = 49 more pounds of food to reach 77 pounds total. At 7 pounds of food per day that's \( \frac{49}{7} \) = 7 more days.
What is \( \frac{1}{5} \) x \( \frac{3}{6} \)?
| \(\frac{1}{10}\) | |
| \(\frac{4}{21}\) | |
| \(\frac{1}{2}\) | |
| \(\frac{4}{15}\) |
To multiply fractions, multiply the numerators together and then multiply the denominators together:
\( \frac{1}{5} \) x \( \frac{3}{6} \) = \( \frac{1 x 3}{5 x 6} \) = \( \frac{3}{30} \) = \(\frac{1}{10}\)
What is \( \frac{4}{7} \) ÷ \( \frac{3}{8} \)?
| 1\(\frac{11}{21}\) | |
| \(\frac{1}{15}\) | |
| 4\(\frac{4}{7}\) | |
| \(\frac{2}{7}\) |
To divide fractions, invert the second fraction and then multiply:
\( \frac{4}{7} \) ÷ \( \frac{3}{8} \) = \( \frac{4}{7} \) x \( \frac{8}{3} \)
To multiply fractions, multiply the numerators together and then multiply the denominators together:
\( \frac{4}{7} \) x \( \frac{8}{3} \) = \( \frac{4 x 8}{7 x 3} \) = \( \frac{32}{21} \) = 1\(\frac{11}{21}\)