ASVAB Arithmetic Reasoning Practice Test 494163 Results

Your Results Global Average
Questions 5 5
Correct 0 3.43
Score 0% 69%

Review

1

Which of the following is not an integer?

77% Answer Correctly

1

-1

0

\({1 \over 2}\)


Solution

An integer is any whole number, including zero. An integer can be either positive or negative. Examples include -77, -1, 0, 55, 119.


2

Alex loaned Ezra $1,300 at an annual interest rate of 9%. If no payments are made, what is the interest owed on this loan at the end of the first year?

74% Answer Correctly
$5
$77
$117
$7

Solution

The yearly interest charged on this loan is the annual interest rate multiplied by the amount borrowed:

interest = annual interest rate x loan amount

i = (\( \frac{6}{100} \)) x $1,300
i = 0.09 x $1,300
i = $117


3

Which of the following is an improper fraction?

70% Answer Correctly

\({a \over 5} \)

\(1 {2 \over 5} \)

\({7 \over 5} \)

\({2 \over 5} \)


Solution

A rational number (or fraction) is represented as a ratio between two integers, a and b, and has the form \({a \over b}\) where a is the numerator and b is the denominator. An improper fraction (\({5 \over 3} \)) has a numerator with a greater absolute value than the denominator and can be converted into a mixed number (\(1 {2 \over 3} \)) which has a whole number part and a fractional part.


4

What is \( \frac{8x^9}{4x^2} \)?

60% Answer Correctly
2x7
2x4\(\frac{1}{2}\)
2x-7
\(\frac{1}{2}\)x11

Solution

To divide terms with exponents, the base of both exponents must be the same. In this case they are so divide the coefficients and subtract the exponents:

\( \frac{8x^9}{4x^2} \)
\( \frac{8}{4} \) x(9 - 2)
2x7


5

If \( \left|z - 5\right| \) + 0 = -4, which of these is a possible value for z?

62% Answer Correctly
4
-2
15
1

Solution

First, solve for \( \left|z - 5\right| \):

\( \left|z - 5\right| \) + 0 = -4
\( \left|z - 5\right| \) = -4 + 0
\( \left|z - 5\right| \) = -4

The value inside the absolute value brackets can be either positive or negative so (z - 5) must equal - 4 or --4 for \( \left|z - 5\right| \) to equal -4:

z - 5 = -4
z = -4 + 5
z = 1
z - 5 = 4
z = 4 + 5
z = 9

So, z = 9 or z = 1.