ASVAB Arithmetic Reasoning Practice Test 494560 Results

Your Results Global Average
Questions 5 5
Correct 0 2.88
Score 0% 58%

Review

1

What is \( 2 \)\( \sqrt{45} \) - \( 4 \)\( \sqrt{5} \)

38% Answer Correctly
8\( \sqrt{225} \)
-2\( \sqrt{225} \)
8\( \sqrt{9} \)
2\( \sqrt{5} \)

Solution

To subtract these radicals together their radicands must be the same:

2\( \sqrt{45} \) - 4\( \sqrt{5} \)
2\( \sqrt{9 \times 5} \) - 4\( \sqrt{5} \)
2\( \sqrt{3^2 \times 5} \) - 4\( \sqrt{5} \)
(2)(3)\( \sqrt{5} \) - 4\( \sqrt{5} \)
6\( \sqrt{5} \) - 4\( \sqrt{5} \)

Now that the radicands are identical, you can subtract them:

6\( \sqrt{5} \) - 4\( \sqrt{5} \)
(6 - 4)\( \sqrt{5} \)
2\( \sqrt{5} \)


2

The __________ is the smallest positive integer that is a multiple of two or more integers.

56% Answer Correctly

absolute value

least common multiple

greatest common factor

least common factor


Solution

The least common multiple (LCM) is the smallest positive integer that is a multiple of two or more integers.


3

Convert 9,426,000 to scientific notation.

62% Answer Correctly
9.426 x 105
9.426 x 106
9.426 x 10-6
9.426 x 10-5

Solution

A number in scientific notation has the format 0.000 x 10exponent. To convert to scientific notation, move the decimal point to the right or the left until the number is a decimal between 1 and 10. The exponent of the 10 is the number of places you moved the decimal point and is positive if you moved the decimal point to the left and negative if you moved it to the right:

9,426,000 in scientific notation is 9.426 x 106


4

What is -4x5 + 2x5?

66% Answer Correctly
-6x-5
6x-5
-2x5
-6x5

Solution

To add or subtract terms with exponents, both the base and the exponent must be the same. In this case they are so add the coefficients and retain the base and exponent:

-4x5 + 2x5
(-4 + 2)x5
-2x5


5

Solve for \( \frac{2!}{5!} \)

66% Answer Correctly
\( \frac{1}{72} \)
9
\( \frac{1}{60} \)
\( \frac{1}{3024} \)

Solution

A factorial is the product of an integer and all the positive integers below it. To solve a fraction featuring factorials, expand the factorials and cancel out like numbers:

\( \frac{2!}{5!} \)
\( \frac{2 \times 1}{5 \times 4 \times 3 \times 2 \times 1} \)
\( \frac{1}{5 \times 4 \times 3} \)
\( \frac{1}{60} \)