| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.74 |
| Score | 0% | 55% |
If \( \left|a + 9\right| \) - 2 = 8, which of these is a possible value for a?
| 7 | |
| -11 | |
| -19 | |
| 12 |
First, solve for \( \left|a + 9\right| \):
\( \left|a + 9\right| \) - 2 = 8
\( \left|a + 9\right| \) = 8 + 2
\( \left|a + 9\right| \) = 10
The value inside the absolute value brackets can be either positive or negative so (a + 9) must equal + 10 or -10 for \( \left|a + 9\right| \) to equal 10:
| a + 9 = 10 a = 10 - 9 a = 1 | a + 9 = -10 a = -10 - 9 a = -19 |
So, a = -19 or a = 1.
A menswear store is having a sale: "Buy one shirt at full price and get another shirt for 5% off." If Bob buys two shirts, each with a regular price of $20, how much will he pay for both shirts?
| $30.00 | |
| $19.00 | |
| $29.00 | |
| $39.00 |
By buying two shirts, Bob will save $20 x \( \frac{5}{100} \) = \( \frac{$20 x 5}{100} \) = \( \frac{$100}{100} \) = $1.00 on the second shirt.
So, his total cost will be
$20.00 + ($20.00 - $1.00)
$20.00 + $19.00
$39.00
What is \( 2 \)\( \sqrt{50} \) + \( 9 \)\( \sqrt{2} \)
| 18\( \sqrt{50} \) | |
| 18\( \sqrt{100} \) | |
| 19\( \sqrt{2} \) | |
| 11\( \sqrt{50} \) |
To add these radicals together their radicands must be the same:
2\( \sqrt{50} \) + 9\( \sqrt{2} \)
2\( \sqrt{25 \times 2} \) + 9\( \sqrt{2} \)
2\( \sqrt{5^2 \times 2} \) + 9\( \sqrt{2} \)
(2)(5)\( \sqrt{2} \) + 9\( \sqrt{2} \)
10\( \sqrt{2} \) + 9\( \sqrt{2} \)
Now that the radicands are identical, you can add them together:
10\( \sqrt{2} \) + 9\( \sqrt{2} \)What is \( \frac{6}{5} \) - \( \frac{5}{9} \)?
| \(\frac{29}{45}\) | |
| 2 \( \frac{6}{12} \) | |
| 2 \( \frac{9}{45} \) | |
| 2 \( \frac{2}{45} \) |
To subtract these fractions, first find the lowest common multiple of their denominators. The first few multiples of 5 are [5, 10, 15, 20, 25, 30, 35, 40, 45, 50] and the first few multiples of 9 are [9, 18, 27, 36, 45, 54, 63, 72, 81, 90]. The first few multiples they share are [45, 90] making 45 the smallest multiple 5 and 9 share.
Next, convert the fractions so each denominator equals the lowest common multiple:
\( \frac{6 x 9}{5 x 9} \) - \( \frac{5 x 5}{9 x 5} \)
\( \frac{54}{45} \) - \( \frac{25}{45} \)
Now, because the fractions share a common denominator, you can subtract them:
\( \frac{54 - 25}{45} \) = \( \frac{29}{45} \) = \(\frac{29}{45}\)
The total water usage for a city is 15,000 gallons each day. Of that total, 12% is for personal use and 39% is for industrial use. How many more gallons of water each day is consumed for industrial use over personal use?
| 5,600 | |
| 4,050 | |
| 4,200 | |
| 8,400 |
39% of the water consumption is industrial use and 12% is personal use so (39% - 12%) = 27% more water is used for industrial purposes. 15,000 gallons are consumed daily so industry consumes \( \frac{27}{100} \) x 15,000 gallons = 4,050 gallons.