| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.17 |
| Score | 0% | 63% |
Find the average of the following numbers: 7, 5, 10, 2.
| 4 | |
| 6 | |
| 5 | |
| 7 |
To find the average of these 4 numbers add them together then divide by 4:
\( \frac{7 + 5 + 10 + 2}{4} \) = \( \frac{24}{4} \) = 6
What is \( 5 \)\( \sqrt{63} \) + \( 4 \)\( \sqrt{7} \)
| 20\( \sqrt{63} \) | |
| 9\( \sqrt{9} \) | |
| 9\( \sqrt{7} \) | |
| 19\( \sqrt{7} \) |
To add these radicals together their radicands must be the same:
5\( \sqrt{63} \) + 4\( \sqrt{7} \)
5\( \sqrt{9 \times 7} \) + 4\( \sqrt{7} \)
5\( \sqrt{3^2 \times 7} \) + 4\( \sqrt{7} \)
(5)(3)\( \sqrt{7} \) + 4\( \sqrt{7} \)
15\( \sqrt{7} \) + 4\( \sqrt{7} \)
Now that the radicands are identical, you can add them together:
15\( \sqrt{7} \) + 4\( \sqrt{7} \)A sports card collection contains football, baseball, and basketball cards. If the ratio of football to baseball cards is 7 to 2 and the ratio of baseball to basketball cards is 7 to 1, what is the ratio of football to basketball cards?
| 9:6 | |
| 3:4 | |
| 49:2 | |
| 3:2 |
The ratio of football cards to baseball cards is 7:2 and the ratio of baseball cards to basketball cards is 7:1. To solve this problem, we need the baseball card side of each ratio to be equal so we need to rewrite the ratios in terms of a common number of baseball cards. (Think of this like finding the common denominator when adding fractions.) The ratio of football to baseball cards can also be written as 49:14 and the ratio of baseball cards to basketball cards as 14:2. So, the ratio of football cards to basketball cards is football:baseball, baseball:basketball or 49:14, 14:2 which reduces to 49:2.
4! = ?
3 x 2 x 1 |
|
5 x 4 x 3 x 2 x 1 |
|
4 x 3 |
|
4 x 3 x 2 x 1 |
A factorial has the form n! and is the product of the integer (n) and all the positive integers below it. For example, 5! = 5 x 4 x 3 x 2 x 1 = 120.
What is the next number in this sequence: 1, 4, 10, 19, 31, __________ ?
| 44 | |
| 38 | |
| 46 | |
| 40 |
The equation for this sequence is:
an = an-1 + 3(n - 1)
where n is the term's order in the sequence, an is the value of the term, and an-1 is the value of the term before an. This makes the next number:
a6 = a5 + 3(6 - 1)
a6 = 31 + 3(5)
a6 = 46