| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.30 |
| Score | 0% | 66% |
Simplify \( \frac{32}{44} \).
| \( \frac{7}{18} \) | |
| \( \frac{5}{16} \) | |
| \( \frac{8}{11} \) | |
| \( \frac{7}{19} \) |
To simplify this fraction, first find the greatest common factor between them. The factors of 32 are [1, 2, 4, 8, 16, 32] and the factors of 44 are [1, 2, 4, 11, 22, 44]. They share 3 factors [1, 2, 4] making 4 their greatest common factor (GCF).
Next, divide both numerator and denominator by the GCF:
\( \frac{32}{44} \) = \( \frac{\frac{32}{4}}{\frac{44}{4}} \) = \( \frac{8}{11} \)
How many 2 gallon cans worth of fuel would you need to pour into an empty 20 gallon tank to fill it exactly halfway?
| 5 | |
| 10 | |
| 5 | |
| 6 |
To fill a 20 gallon tank exactly halfway you'll need 10 gallons of fuel. Each fuel can holds 2 gallons so:
cans = \( \frac{10 \text{ gallons}}{2 \text{ gallons}} \) = 5
How many 7-passenger vans will it take to drive all 78 members of the football team to an away game?
| 10 vans | |
| 9 vans | |
| 3 vans | |
| 12 vans |
Calculate the number of vans needed by dividing the number of people that need transported by the capacity of one van:
vans = \( \frac{78}{7} \) = 11\(\frac{1}{7}\)
So, it will take 11 full vans and one partially full van to transport the entire team making a total of 12 vans.
What is \( \frac{4}{6} \) ÷ \( \frac{2}{6} \)?
| 2 | |
| 4 | |
| \(\frac{2}{7}\) | |
| \(\frac{4}{35}\) |
To divide fractions, invert the second fraction and then multiply:
\( \frac{4}{6} \) ÷ \( \frac{2}{6} \) = \( \frac{4}{6} \) x \( \frac{6}{2} \)
To multiply fractions, multiply the numerators together and then multiply the denominators together:
\( \frac{4}{6} \) x \( \frac{6}{2} \) = \( \frac{4 x 6}{6 x 2} \) = \( \frac{24}{12} \) = 2
Solve 2 + (4 + 2) ÷ 5 x 5 - 52
| 1\(\frac{2}{7}\) | |
| 2\(\frac{1}{4}\) | |
| \(\frac{5}{9}\) | |
| -17 |
Use PEMDAS (Parentheses, Exponents, Multipy/Divide, Add/Subtract):
2 + (4 + 2) ÷ 5 x 5 - 52
P: 2 + (6) ÷ 5 x 5 - 52
E: 2 + 6 ÷ 5 x 5 - 25
MD: 2 + \( \frac{6}{5} \) x 5 - 25
MD: 2 + \( \frac{30}{5} \) - 25
AS: \( \frac{10}{5} \) + \( \frac{30}{5} \) - 25
AS: \( \frac{40}{5} \) - 25
AS: \( \frac{40 - 125}{5} \)
\( \frac{-85}{5} \)
-17