| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.26 |
| Score | 0% | 65% |
What is the least common multiple of 3 and 9?
| 18 | |
| 9 | |
| 2 | |
| 8 |
The first few multiples of 3 are [3, 6, 9, 12, 15, 18, 21, 24, 27, 30] and the first few multiples of 9 are [9, 18, 27, 36, 45, 54, 63, 72, 81, 90]. The first few multiples they share are [9, 18, 27, 36, 45] making 9 the smallest multiple 3 and 9 have in common.
\({b + c \over a} = {b \over a} + {c \over a}\) defines which of the following?
distributive property for multiplication |
|
commutative property for multiplication |
|
commutative property for division |
|
distributive property for division |
The distributive property for division helps in solving expressions like \({b + c \over a}\). It specifies that the result of dividing a fraction with multiple terms in the numerator and one term in the denominator can be obtained by dividing each term individually and then totaling the results: \({b + c \over a} = {b \over a} + {c \over a}\). For example, \({a^3 + 6a^2 \over a^2} = {a^3 \over a^2} + {6a^2 \over a^2} = a + 6\).
Which of the following is an improper fraction?
\({7 \over 5} \) |
|
\({a \over 5} \) |
|
\({2 \over 5} \) |
|
\(1 {2 \over 5} \) |
A rational number (or fraction) is represented as a ratio between two integers, a and b, and has the form \({a \over b}\) where a is the numerator and b is the denominator. An improper fraction (\({5 \over 3} \)) has a numerator with a greater absolute value than the denominator and can be converted into a mixed number (\(1 {2 \over 3} \)) which has a whole number part and a fractional part.
Solve 4 + (5 + 3) ÷ 4 x 4 - 32
| 3 | |
| \(\frac{5}{6}\) | |
| 2\(\frac{1}{4}\) | |
| 1 |
Use PEMDAS (Parentheses, Exponents, Multipy/Divide, Add/Subtract):
4 + (5 + 3) ÷ 4 x 4 - 32
P: 4 + (8) ÷ 4 x 4 - 32
E: 4 + 8 ÷ 4 x 4 - 9
MD: 4 + \( \frac{8}{4} \) x 4 - 9
MD: 4 + \( \frac{32}{4} \) - 9
AS: \( \frac{16}{4} \) + \( \frac{32}{4} \) - 9
AS: \( \frac{48}{4} \) - 9
AS: \( \frac{48 - 36}{4} \)
\( \frac{12}{4} \)
3
10 members of a bridal party need transported to a wedding reception but there are only 2 3-passenger taxis available to take them. How many will need to find other transportation?
| 1 | |
| 6 | |
| 7 | |
| 4 |
There are 2 3-passenger taxis available so that's 2 x 3 = 6 total seats. There are 10 people needing transportation leaving 10 - 6 = 4 who will have to find other transportation.