| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.37 |
| Score | 0% | 67% |
A triathlon course includes a 200m swim, a 20.5km bike ride, and a 11.5km run. What is the total length of the race course?
| 39.4km | |
| 40.8km | |
| 51.3km | |
| 32.2km |
To add these distances, they must share the same unit so first you need to first convert the swim distance from meters (m) to kilometers (km) before adding it to the bike and run distances which are already in km. To convert 200 meters to kilometers, divide the distance by 1000 to get 0.2km then add the remaining distances:
total distance = swim + bike + run
total distance = 0.2km + 20.5km + 11.5km
total distance = 32.2km
Which of these numbers is a factor of 16?
| 4 | |
| 2 | |
| 10 | |
| 18 |
The factors of a number are all positive integers that divide evenly into the number. The factors of 16 are 1, 2, 4, 8, 16.
What is 5\( \sqrt{4} \) x 7\( \sqrt{2} \)?
| 12\( \sqrt{4} \) | |
| 70\( \sqrt{2} \) | |
| 35\( \sqrt{6} \) | |
| 35\( \sqrt{2} \) |
To multiply terms with radicals, multiply the coefficients and radicands separately:
5\( \sqrt{4} \) x 7\( \sqrt{2} \)
(5 x 7)\( \sqrt{4 \times 2} \)
35\( \sqrt{8} \)
Now we need to simplify the radical:
35\( \sqrt{8} \)
35\( \sqrt{2 \times 4} \)
35\( \sqrt{2 \times 2^2} \)
(35)(2)\( \sqrt{2} \)
70\( \sqrt{2} \)
21 members of a bridal party need transported to a wedding reception but there are only 4 5-passenger taxis available to take them. How many will need to find other transportation?
| 1 | |
| 7 | |
| 5 | |
| 6 |
There are 4 5-passenger taxis available so that's 4 x 5 = 20 total seats. There are 21 people needing transportation leaving 21 - 20 = 1 who will have to find other transportation.
How many hours does it take a car to travel 75 miles at an average speed of 75 miles per hour?
| 1 hour | |
| 9 hours | |
| 3 hours | |
| 8 hours |
Average speed in miles per hour is the number of miles traveled divided by the number of hours:
speed = \( \frac{\text{distance}}{\text{time}} \)Solving for time:
time = \( \frac{\text{distance}}{\text{speed}} \)
time = \( \frac{75mi}{75mph} \)
1 hour