ASVAB Arithmetic Reasoning Practice Test 498617 Results

Your Results Global Average
Questions 5 5
Correct 0 3.15
Score 0% 63%

Review

1

What is -7z3 - 3z3?

71% Answer Correctly
10z-3
-10z3
-4z3
-4z9

Solution

To add or subtract terms with exponents, both the base and the exponent must be the same. In this case they are so subtract the coefficients and retain the base and exponent:

-7z3 - 3z3
(-7 - 3)z3
-10z3


2

Christine scored 94% on her final exam. If each question was worth 3 points and there were 210 possible points on the exam, how many questions did Christine answer correctly?

57% Answer Correctly
75
66
62
59

Solution

Christine scored 94% on the test meaning she earned 94% of the possible points on the test. There were 210 possible points on the test so she earned 210 x 0.94 = 198 points. Each question is worth 3 points so she got \( \frac{198}{3} \) = 66 questions right.


3

What is \( 8 \)\( \sqrt{63} \) - \( 6 \)\( \sqrt{7} \)

39% Answer Correctly
18\( \sqrt{7} \)
2\( \sqrt{63} \)
48\( \sqrt{7} \)
48\( \sqrt{9} \)

Solution

To subtract these radicals together their radicands must be the same:

8\( \sqrt{63} \) - 6\( \sqrt{7} \)
8\( \sqrt{9 \times 7} \) - 6\( \sqrt{7} \)
8\( \sqrt{3^2 \times 7} \) - 6\( \sqrt{7} \)
(8)(3)\( \sqrt{7} \) - 6\( \sqrt{7} \)
24\( \sqrt{7} \) - 6\( \sqrt{7} \)

Now that the radicands are identical, you can subtract them:

24\( \sqrt{7} \) - 6\( \sqrt{7} \)
(24 - 6)\( \sqrt{7} \)
18\( \sqrt{7} \)


4

What is \( \frac{1}{6} \) x \( \frac{1}{7} \)?

72% Answer Correctly
\(\frac{2}{25}\)
\(\frac{1}{42}\)
\(\frac{1}{7}\)
\(\frac{8}{27}\)

Solution

To multiply fractions, multiply the numerators together and then multiply the denominators together:

\( \frac{1}{6} \) x \( \frac{1}{7} \) = \( \frac{1 x 1}{6 x 7} \) = \( \frac{1}{42} \) = \(\frac{1}{42}\)


5

a(b + c) = ab + ac defines which of the following?

74% Answer Correctly

commutative property for division

commutative property for multiplication

distributive property for division

distributive property for multiplication


Solution

The distributive property for multiplication helps in solving expressions like a(b + c). It specifies that the result of multiplying one number by the sum or difference of two numbers can be obtained by multiplying each number individually and then totaling the results: a(b + c) = ab + ac. For example, 4(10-5) = (4 x 10) - (4 x 5) = 40 - 20 = 20.