ASVAB Arithmetic Reasoning Practice Test 499400 Results

Your Results Global Average
Questions 5 5
Correct 0 3.42
Score 0% 68%

Review

1

What is 9z2 + 7z2?

66% Answer Correctly
2z-2
-2z-2
16z2
2z2

Solution

To add or subtract terms with exponents, both the base and the exponent must be the same. In this case they are so add the coefficients and retain the base and exponent:

9z2 + 7z2
(9 + 7)z2
16z2


2

What is the least common multiple of 2 and 6?

72% Answer Correctly
1
8
6
7

Solution

The first few multiples of 2 are [2, 4, 6, 8, 10, 12, 14, 16, 18, 20] and the first few multiples of 6 are [6, 12, 18, 24, 30, 36, 42, 48, 54, 60]. The first few multiples they share are [6, 12, 18, 24, 30] making 6 the smallest multiple 2 and 6 have in common.


3

What is the next number in this sequence: 1, 4, 7, 10, 13, __________ ?

92% Answer Correctly
23
16
17
7

Solution

The equation for this sequence is:

an = an-1 + 3

where n is the term's order in the sequence, an is the value of the term, and an-1 is the value of the term before an. This makes the next number:

a6 = a5 + 3
a6 = 13 + 3
a6 = 16


4

What is \( 5 \)\( \sqrt{20} \) - \( 3 \)\( \sqrt{5} \)

38% Answer Correctly
2\( \sqrt{5} \)
7\( \sqrt{5} \)
2\( \sqrt{100} \)
15\( \sqrt{100} \)

Solution

To subtract these radicals together their radicands must be the same:

5\( \sqrt{20} \) - 3\( \sqrt{5} \)
5\( \sqrt{4 \times 5} \) - 3\( \sqrt{5} \)
5\( \sqrt{2^2 \times 5} \) - 3\( \sqrt{5} \)
(5)(2)\( \sqrt{5} \) - 3\( \sqrt{5} \)
10\( \sqrt{5} \) - 3\( \sqrt{5} \)

Now that the radicands are identical, you can subtract them:

10\( \sqrt{5} \) - 3\( \sqrt{5} \)
(10 - 3)\( \sqrt{5} \)
7\( \sqrt{5} \)


5

Ezra loaned Charlie $1,300 at an annual interest rate of 5%. If no payments are made, what is the interest owed on this loan at the end of the first year?

74% Answer Correctly
$14
$7
$55
$65

Solution

The yearly interest charged on this loan is the annual interest rate multiplied by the amount borrowed:

interest = annual interest rate x loan amount

i = (\( \frac{6}{100} \)) x $1,300
i = 0.05 x $1,300
i = $65