| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.21 |
| Score | 0% | 64% |
What is \( \frac{3}{8} \) x \( \frac{1}{7} \)?
| \(\frac{3}{56}\) | |
| \(\frac{1}{7}\) | |
| \(\frac{2}{15}\) | |
| \(\frac{3}{7}\) |
To multiply fractions, multiply the numerators together and then multiply the denominators together:
\( \frac{3}{8} \) x \( \frac{1}{7} \) = \( \frac{3 x 1}{8 x 7} \) = \( \frac{3}{56} \) = \(\frac{3}{56}\)
Convert c-4 to remove the negative exponent.
| \( \frac{-1}{-4c} \) | |
| \( \frac{-4}{-c} \) | |
| \( \frac{1}{c^{-4}} \) | |
| \( \frac{1}{c^4} \) |
To convert a negative exponent to a positive exponent, calculate the positive exponent then take the reciprocal.
If all of a roofing company's 9 workers are required to staff 3 roofing crews, how many workers need to be added during the busy season in order to send 8 complete crews out on jobs?
| 3 | |
| 4 | |
| 19 | |
| 15 |
In order to find how many additional workers are needed to staff the extra crews you first need to calculate how many workers are on a crew. There are 9 workers at the company now and that's enough to staff 3 crews so there are \( \frac{9}{3} \) = 3 workers on a crew. 8 crews are needed for the busy season which, at 3 workers per crew, means that the roofing company will need 8 x 3 = 24 total workers to staff the crews during the busy season. The company already employs 9 workers so they need to add 24 - 9 = 15 new staff for the busy season.
Christine scored 80% on her final exam. If each question was worth 3 points and there were 270 possible points on the exam, how many questions did Christine answer correctly?
| 77 | |
| 72 | |
| 64 | |
| 65 |
Christine scored 80% on the test meaning she earned 80% of the possible points on the test. There were 270 possible points on the test so she earned 270 x 0.8 = 216 points. Each question is worth 3 points so she got \( \frac{216}{3} \) = 72 questions right.
What is the next number in this sequence: 1, 4, 10, 19, 31, __________ ?
| 47 | |
| 54 | |
| 37 | |
| 46 |
The equation for this sequence is:
an = an-1 + 3(n - 1)
where n is the term's order in the sequence, an is the value of the term, and an-1 is the value of the term before an. This makes the next number:
a6 = a5 + 3(6 - 1)
a6 = 31 + 3(5)
a6 = 46