ASVAB Arithmetic Reasoning Practice Test 50101 Results

Your Results Global Average
Questions 5 5
Correct 0 3.39
Score 0% 68%

Review

1

What is \( \frac{2}{9} \) x \( \frac{1}{7} \)?

72% Answer Correctly
\(\frac{2}{63}\)
\(\frac{16}{81}\)
\(\frac{1}{7}\)
\(\frac{1}{10}\)

Solution

To multiply fractions, multiply the numerators together and then multiply the denominators together:

\( \frac{2}{9} \) x \( \frac{1}{7} \) = \( \frac{2 x 1}{9 x 7} \) = \( \frac{2}{63} \) = \(\frac{2}{63}\)


2

12 members of a bridal party need transported to a wedding reception but there are only 2 4-passenger taxis available to take them. How many will need to find other transportation?

75% Answer Correctly
8
7
4
9

Solution

There are 2 4-passenger taxis available so that's 2 x 4 = 8 total seats. There are 12 people needing transportation leaving 12 - 8 = 4 who will have to find other transportation.


3

A tiger in a zoo has consumed 44 pounds of food in 4 days. If the tiger continues to eat at the same rate, in how many more days will its total food consumtion be 99 pounds?

56% Answer Correctly
2
4
5
9

Solution

If the tiger has consumed 44 pounds of food in 4 days that's \( \frac{44}{4} \) = 11 pounds of food per day. The tiger needs to consume 99 - 44 = 55 more pounds of food to reach 99 pounds total. At 11 pounds of food per day that's \( \frac{55}{11} \) = 5 more days.


4

Which of the following is not an integer?

77% Answer Correctly

0

1

\({1 \over 2}\)

-1


Solution

An integer is any whole number, including zero. An integer can be either positive or negative. Examples include -77, -1, 0, 55, 119.


5

\({b + c \over a} = {b \over a} + {c \over a}\) defines which of the following?

55% Answer Correctly

distributive property for multiplication

commutative property for multiplication

commutative property for division

distributive property for division


Solution

The distributive property for division helps in solving expressions like \({b + c \over a}\). It specifies that the result of dividing a fraction with multiple terms in the numerator and one term in the denominator can be obtained by dividing each term individually and then totaling the results: \({b + c \over a} = {b \over a} + {c \over a}\). For example, \({a^3 + 6a^2 \over a^2} = {a^3 \over a^2} + {6a^2 \over a^2} = a + 6\).