| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.07 |
| Score | 0% | 61% |
A bread recipe calls for 3\(\frac{5}{8}\) cups of flour. If you only have \(\frac{1}{2}\) cup, how much more flour is needed?
| 2\(\frac{1}{8}\) cups | |
| 3\(\frac{1}{8}\) cups | |
| 1\(\frac{5}{8}\) cups | |
| 2\(\frac{3}{8}\) cups |
The amount of flour you need is (3\(\frac{5}{8}\) - \(\frac{1}{2}\)) cups. Rewrite the quantities so they share a common denominator and subtract:
(\( \frac{29}{8} \) - \( \frac{4}{8} \)) cups
\( \frac{25}{8} \) cups
3\(\frac{1}{8}\) cups
Convert b-4 to remove the negative exponent.
| \( \frac{-1}{-4b} \) | |
| \( \frac{1}{b^4} \) | |
| \( \frac{-1}{b^{-4}} \) | |
| \( \frac{4}{b} \) |
To convert a negative exponent to a positive exponent, calculate the positive exponent then take the reciprocal.
Solve 4 + (4 + 3) ÷ 5 x 4 - 42
| \(\frac{7}{8}\) | |
| 3 | |
| -6\(\frac{2}{5}\) | |
| 1 |
Use PEMDAS (Parentheses, Exponents, Multipy/Divide, Add/Subtract):
4 + (4 + 3) ÷ 5 x 4 - 42
P: 4 + (7) ÷ 5 x 4 - 42
E: 4 + 7 ÷ 5 x 4 - 16
MD: 4 + \( \frac{7}{5} \) x 4 - 16
MD: 4 + \( \frac{28}{5} \) - 16
AS: \( \frac{20}{5} \) + \( \frac{28}{5} \) - 16
AS: \( \frac{48}{5} \) - 16
AS: \( \frac{48 - 80}{5} \)
\( \frac{-32}{5} \)
-6\(\frac{2}{5}\)
4! = ?
4 x 3 |
|
5 x 4 x 3 x 2 x 1 |
|
4 x 3 x 2 x 1 |
|
3 x 2 x 1 |
A factorial has the form n! and is the product of the integer (n) and all the positive integers below it. For example, 5! = 5 x 4 x 3 x 2 x 1 = 120.
What is 7\( \sqrt{5} \) x 5\( \sqrt{5} \)?
| 175 | |
| 12\( \sqrt{25} \) | |
| 35\( \sqrt{10} \) | |
| 35\( \sqrt{5} \) |
To multiply terms with radicals, multiply the coefficients and radicands separately:
7\( \sqrt{5} \) x 5\( \sqrt{5} \)
(7 x 5)\( \sqrt{5 \times 5} \)
35\( \sqrt{25} \)
Now we need to simplify the radical:
35\( \sqrt{25} \)
35\( \sqrt{5^2} \)
(35)(5)
175