ASVAB Arithmetic Reasoning Practice Test 503712 Results

Your Results Global Average
Questions 5 5
Correct 0 3.06
Score 0% 61%

Review

1

This property states taht the order of addition or multiplication does not mater. For example, 2 + 5 and 5 + 2 are equivalent.

59% Answer Correctly

commutative

distributive

PEDMAS

associative


Solution

The commutative property states that, when adding or multiplying numbers, the order in which they're added or multiplied does not matter. For example, 3 + 4 and 4 + 3 give the same result, as do 3 x 4 and 4 x 3.


2

If a mayor is elected with 81% of the votes cast and 40% of a town's 43,000 voters cast a vote, how many votes did the mayor receive?

49% Answer Correctly
9,460
13,932
15,136
10,836

Solution

If 40% of the town's 43,000 voters cast ballots the number of votes cast is:

(\( \frac{40}{100} \)) x 43,000 = \( \frac{1,720,000}{100} \) = 17,200

The mayor got 81% of the votes cast which is:

(\( \frac{81}{100} \)) x 17,200 = \( \frac{1,393,200}{100} \) = 13,932 votes.


3

What is the next number in this sequence: 1, 8, 15, 22, 29, __________ ?

92% Answer Correctly
27
44
36
37

Solution

The equation for this sequence is:

an = an-1 + 7

where n is the term's order in the sequence, an is the value of the term, and an-1 is the value of the term before an. This makes the next number:

a6 = a5 + 7
a6 = 29 + 7
a6 = 36


4

If the ratio of home fans to visiting fans in a crowd is 4:1 and all 50,000 seats in a stadium are filled, how many home fans are in attendance?

50% Answer Correctly
30,000
35,833
30,833
40,000

Solution

A ratio of 4:1 means that there are 4 home fans for every one visiting fan. So, of every 5 fans, 4 are home fans and \( \frac{4}{5} \) of every fan in the stadium is a home fan:

50,000 fans x \( \frac{4}{5} \) = \( \frac{200000}{5} \) = 40,000 fans.


5

If all of a roofing company's 12 workers are required to staff 4 roofing crews, how many workers need to be added during the busy season in order to send 8 complete crews out on jobs?

55% Answer Correctly
16
8
12
2

Solution

In order to find how many additional workers are needed to staff the extra crews you first need to calculate how many workers are on a crew. There are 12 workers at the company now and that's enough to staff 4 crews so there are \( \frac{12}{4} \) = 3 workers on a crew. 8 crews are needed for the busy season which, at 3 workers per crew, means that the roofing company will need 8 x 3 = 24 total workers to staff the crews during the busy season. The company already employs 12 workers so they need to add 24 - 12 = 12 new staff for the busy season.