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|---|---|---|
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This property states taht the order of addition or multiplication does not mater. For example, 2 + 5 and 5 + 2 are equivalent.
commutative |
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distributive |
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PEDMAS |
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associative |
The commutative property states that, when adding or multiplying numbers, the order in which they're added or multiplied does not matter. For example, 3 + 4 and 4 + 3 give the same result, as do 3 x 4 and 4 x 3.
If a mayor is elected with 81% of the votes cast and 40% of a town's 43,000 voters cast a vote, how many votes did the mayor receive?
| 9,460 | |
| 13,932 | |
| 15,136 | |
| 10,836 |
If 40% of the town's 43,000 voters cast ballots the number of votes cast is:
(\( \frac{40}{100} \)) x 43,000 = \( \frac{1,720,000}{100} \) = 17,200
The mayor got 81% of the votes cast which is:
(\( \frac{81}{100} \)) x 17,200 = \( \frac{1,393,200}{100} \) = 13,932 votes.
What is the next number in this sequence: 1, 8, 15, 22, 29, __________ ?
| 27 | |
| 44 | |
| 36 | |
| 37 |
The equation for this sequence is:
an = an-1 + 7
where n is the term's order in the sequence, an is the value of the term, and an-1 is the value of the term before an. This makes the next number:
a6 = a5 + 7
a6 = 29 + 7
a6 = 36
If the ratio of home fans to visiting fans in a crowd is 4:1 and all 50,000 seats in a stadium are filled, how many home fans are in attendance?
| 30,000 | |
| 35,833 | |
| 30,833 | |
| 40,000 |
A ratio of 4:1 means that there are 4 home fans for every one visiting fan. So, of every 5 fans, 4 are home fans and \( \frac{4}{5} \) of every fan in the stadium is a home fan:
50,000 fans x \( \frac{4}{5} \) = \( \frac{200000}{5} \) = 40,000 fans.
If all of a roofing company's 12 workers are required to staff 4 roofing crews, how many workers need to be added during the busy season in order to send 8 complete crews out on jobs?
| 16 | |
| 8 | |
| 12 | |
| 2 |
In order to find how many additional workers are needed to staff the extra crews you first need to calculate how many workers are on a crew. There are 12 workers at the company now and that's enough to staff 4 crews so there are \( \frac{12}{4} \) = 3 workers on a crew. 8 crews are needed for the busy season which, at 3 workers per crew, means that the roofing company will need 8 x 3 = 24 total workers to staff the crews during the busy season. The company already employs 12 workers so they need to add 24 - 12 = 12 new staff for the busy season.