ASVAB Arithmetic Reasoning Practice Test 503735 Results

Your Results Global Average
Questions 5 5
Correct 0 3.48
Score 0% 70%

Review

1

What is \( \frac{-4a^9}{1a^2} \)?

60% Answer Correctly
-4a11
-\(\frac{1}{4}\)a-7
-4a7
-\(\frac{1}{4}\)a7

Solution

To divide terms with exponents, the base of both exponents must be the same. In this case they are so divide the coefficients and subtract the exponents:

\( \frac{-4a^9}{a^2} \)
\( \frac{-4}{1} \) a(9 - 2)
-4a7


2

Convert x-3 to remove the negative exponent.

68% Answer Correctly
\( \frac{-1}{x^{-3}} \)
\( \frac{-1}{-3x} \)
\( \frac{3}{x} \)
\( \frac{1}{x^3} \)

Solution

To convert a negative exponent to a positive exponent, calculate the positive exponent then take the reciprocal.


3

Simplify \( \frac{20}{68} \).

77% Answer Correctly
\( \frac{9}{20} \)
\( \frac{7}{17} \)
\( \frac{5}{17} \)
\( \frac{1}{3} \)

Solution

To simplify this fraction, first find the greatest common factor between them. The factors of 20 are [1, 2, 4, 5, 10, 20] and the factors of 68 are [1, 2, 4, 17, 34, 68]. They share 3 factors [1, 2, 4] making 4 their greatest common factor (GCF).

Next, divide both numerator and denominator by the GCF:

\( \frac{20}{68} \) = \( \frac{\frac{20}{4}}{\frac{68}{4}} \) = \( \frac{5}{17} \)


4

If a car travels 350 miles in 5 hours, what is the average speed?

86% Answer Correctly
70 mph
75 mph
60 mph
40 mph

Solution

Average speed in miles per hour is the number of miles traveled divided by the number of hours:

speed = \( \frac{\text{distance}}{\text{time}} \)
speed = \( \frac{350mi}{5h} \)
70 mph


5

\({b + c \over a} = {b \over a} + {c \over a}\) defines which of the following?

56% Answer Correctly

commutative property for multiplication

commutative property for division

distributive property for division

distributive property for multiplication


Solution

The distributive property for division helps in solving expressions like \({b + c \over a}\). It specifies that the result of dividing a fraction with multiple terms in the numerator and one term in the denominator can be obtained by dividing each term individually and then totaling the results: \({b + c \over a} = {b \over a} + {c \over a}\). For example, \({a^3 + 6a^2 \over a^2} = {a^3 \over a^2} + {6a^2 \over a^2} = a + 6\).