| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.48 |
| Score | 0% | 70% |
What is \( \frac{-4a^9}{1a^2} \)?
| -4a11 | |
| -\(\frac{1}{4}\)a-7 | |
| -4a7 | |
| -\(\frac{1}{4}\)a7 |
To divide terms with exponents, the base of both exponents must be the same. In this case they are so divide the coefficients and subtract the exponents:
\( \frac{-4a^9}{a^2} \)
\( \frac{-4}{1} \) a(9 - 2)
-4a7
Convert x-3 to remove the negative exponent.
| \( \frac{-1}{x^{-3}} \) | |
| \( \frac{-1}{-3x} \) | |
| \( \frac{3}{x} \) | |
| \( \frac{1}{x^3} \) |
To convert a negative exponent to a positive exponent, calculate the positive exponent then take the reciprocal.
Simplify \( \frac{20}{68} \).
| \( \frac{9}{20} \) | |
| \( \frac{7}{17} \) | |
| \( \frac{5}{17} \) | |
| \( \frac{1}{3} \) |
To simplify this fraction, first find the greatest common factor between them. The factors of 20 are [1, 2, 4, 5, 10, 20] and the factors of 68 are [1, 2, 4, 17, 34, 68]. They share 3 factors [1, 2, 4] making 4 their greatest common factor (GCF).
Next, divide both numerator and denominator by the GCF:
\( \frac{20}{68} \) = \( \frac{\frac{20}{4}}{\frac{68}{4}} \) = \( \frac{5}{17} \)
If a car travels 350 miles in 5 hours, what is the average speed?
| 70 mph | |
| 75 mph | |
| 60 mph | |
| 40 mph |
Average speed in miles per hour is the number of miles traveled divided by the number of hours:
speed = \( \frac{\text{distance}}{\text{time}} \)\({b + c \over a} = {b \over a} + {c \over a}\) defines which of the following?
commutative property for multiplication |
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commutative property for division |
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distributive property for division |
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distributive property for multiplication |
The distributive property for division helps in solving expressions like \({b + c \over a}\). It specifies that the result of dividing a fraction with multiple terms in the numerator and one term in the denominator can be obtained by dividing each term individually and then totaling the results: \({b + c \over a} = {b \over a} + {c \over a}\). For example, \({a^3 + 6a^2 \over a^2} = {a^3 \over a^2} + {6a^2 \over a^2} = a + 6\).