If a single cook can bake 2 large cakes per hour and the kitchen is available for 4 hours, a single cook can bake 2 x 4 = 8 large cakes during that time. 36 large cakes are needed for the party so \( \frac{36}{8} \) = 4\(\frac{1}{2}\) cooks are needed to bake the required number of large cakes.

If a single cook can bake 14 small cakes per hour and the kitchen is available for 4 hours, a single cook can bake 14 x 4 = 56 small cakes during that time. 450 small cakes are needed for the party so \( \frac{450}{56} \) = 8\(\frac{1}{28}\) cooks are needed to bake the required number of small cakes.

Because you can't employ a fractional cook, round the number of cooks needed for each type of cake up to the next whole number resulting in 5 + 9 = 14 cooks.

By buying two shirts, Roger will save $19 x \( \frac{20}{100} \) = \( \frac{$19 x 20}{100} \) = \( \frac{$380}{100} \) = $3.80 on the second shirt.

So, his total cost will be
$19.00 + ($19.00 - $3.80)
$19.00 + $15.20
$34.20

The least common multiple (LCM) is the smallest positive integer that is a multiple of two or more integers.

To add these radicals together their radicands must be the same:

6\( \sqrt{12} \) + 9\( \sqrt{3} \)
6\( \sqrt{4 \times 3} \) + 9\( \sqrt{3} \)
6\( \sqrt{2^2 \times 3} \) + 9\( \sqrt{3} \)
(6)(2)\( \sqrt{3} \) + 9\( \sqrt{3} \)
12\( \sqrt{3} \) + 9\( \sqrt{3} \)

Now that the radicands are identical, you can add them together:

To raise a term with an exponent to another exponent, retain the base and multiply the exponents: