| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.04 |
| Score | 0% | 61% |
If a rectangle is twice as long as it is wide and has a perimeter of 48 meters, what is the area of the rectangle?
| 32 m2 | |
| 128 m2 | |
| 8 m2 | |
| 98 m2 |
The area of a rectangle is width (w) x height (h). In this problem we know that the rectangle is twice as long as it is wide so h = 2w. The perimeter of a rectangle is 2w + 2h and we know that the perimeter of this rectangle is 48 meters so the equation becomes: 2w + 2h = 48.
Putting these two equations together and solving for width (w):
2w + 2h = 48
w + h = \( \frac{48}{2} \)
w + h = 24
w = 24 - h
From the question we know that h = 2w so substituting 2w for h gives us:
w = 24 - 2w
3w = 24
w = \( \frac{24}{3} \)
w = 8
Since h = 2w that makes h = (2 x 8) = 16 and the area = h x w = 8 x 16 = 128 m2
What is -c6 x 9c3?
| 8c9 | |
| 8c6 | |
| -9c9 | |
| -9c18 |
To multiply terms with exponents, the base of both exponents must be the same. In this case they are so multiply the coefficients and add the exponents:
-c6 x 9c3
(-1 x 9)c(6 + 3)
-9c9
The __________ is the smallest positive integer that is a multiple of two or more integers.
greatest common factor |
|
absolute value |
|
least common factor |
|
least common multiple |
The least common multiple (LCM) is the smallest positive integer that is a multiple of two or more integers.
Find the average of the following numbers: 9, 7, 11, 5.
| 8 | |
| 9 | |
| 3 | |
| 6 |
To find the average of these 4 numbers add them together then divide by 4:
\( \frac{9 + 7 + 11 + 5}{4} \) = \( \frac{32}{4} \) = 8
A sports card collection contains football, baseball, and basketball cards. If the ratio of football to baseball cards is 3 to 2 and the ratio of baseball to basketball cards is 3 to 1, what is the ratio of football to basketball cards?
| 1:1 | |
| 5:2 | |
| 5:8 | |
| 9:2 |
The ratio of football cards to baseball cards is 3:2 and the ratio of baseball cards to basketball cards is 3:1. To solve this problem, we need the baseball card side of each ratio to be equal so we need to rewrite the ratios in terms of a common number of baseball cards. (Think of this like finding the common denominator when adding fractions.) The ratio of football to baseball cards can also be written as 9:6 and the ratio of baseball cards to basketball cards as 6:2. So, the ratio of football cards to basketball cards is football:baseball, baseball:basketball or 9:6, 6:2 which reduces to 9:2.