| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.48 |
| Score | 0% | 70% |
Jennifer scored 76% on her final exam. If each question was worth 3 points and there were 210 possible points on the exam, how many questions did Jennifer answer correctly?
| 53 | |
| 46 | |
| 57 | |
| 50 |
Jennifer scored 76% on the test meaning she earned 76% of the possible points on the test. There were 210 possible points on the test so she earned 210 x 0.76 = 159 points. Each question is worth 3 points so she got \( \frac{159}{3} \) = 53 questions right.
Solve for \( \frac{5!}{4!} \)
| 5 | |
| \( \frac{1}{60480} \) | |
| 15120 | |
| \( \frac{1}{3024} \) |
A factorial is the product of an integer and all the positive integers below it. To solve a fraction featuring factorials, expand the factorials and cancel out like numbers:
\( \frac{5!}{4!} \)
\( \frac{5 \times 4 \times 3 \times 2 \times 1}{4 \times 3 \times 2 \times 1} \)
\( \frac{5}{1} \)
5
What is \( \frac{-8b^5}{5b^2} \)?
| -1\(\frac{3}{5}\)b2\(\frac{1}{2}\) | |
| -1\(\frac{3}{5}\)b-3 | |
| -1\(\frac{3}{5}\)b\(\frac{2}{5}\) | |
| -1\(\frac{3}{5}\)b3 |
To divide terms with exponents, the base of both exponents must be the same. In this case they are so divide the coefficients and subtract the exponents:
\( \frac{-8b^5}{5b^2} \)
\( \frac{-8}{5} \) b(5 - 2)
-1\(\frac{3}{5}\)b3
What is the next number in this sequence: 1, 6, 11, 16, 21, __________ ?
| 26 | |
| 23 | |
| 35 | |
| 31 |
The equation for this sequence is:
an = an-1 + 5
where n is the term's order in the sequence, an is the value of the term, and an-1 is the value of the term before an. This makes the next number:
a6 = a5 + 5
a6 = 21 + 5
a6 = 26
What is the least common multiple of 6 and 8?
| 35 | |
| 24 | |
| 27 | |
| 2 |
The first few multiples of 6 are [6, 12, 18, 24, 30, 36, 42, 48, 54, 60] and the first few multiples of 8 are [8, 16, 24, 32, 40, 48, 56, 64, 72, 80]. The first few multiples they share are [24, 48, 72, 96] making 24 the smallest multiple 6 and 8 have in common.