| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.10 |
| Score | 0% | 62% |
16 members of a bridal party need transported to a wedding reception but there are only 3 5-passenger taxis available to take them. How many will need to find other transportation?
| 1 | |
| 7 | |
| 6 | |
| 3 |
There are 3 5-passenger taxis available so that's 3 x 5 = 15 total seats. There are 16 people needing transportation leaving 16 - 15 = 1 who will have to find other transportation.
A circular logo is enlarged to fit the lid of a jar. The new diameter is 45% larger than the original. By what percentage has the area of the logo increased?
| 30% | |
| 15% | |
| 22\(\frac{1}{2}\)% | |
| 20% |
The area of a circle is given by the formula A = πr2 where r is the radius of the circle. The radius of a circle is its diameter divided by two so A = π(\( \frac{d}{2} \))2. If the diameter of the logo increases by 45% the radius (and, consequently, the total area) increases by \( \frac{45\text{%}}{2} \) = 22\(\frac{1}{2}\)%
Find the average of the following numbers: 9, 5, 8, 6.
| 12 | |
| 7 | |
| 10 | |
| 11 |
To find the average of these 4 numbers add them together then divide by 4:
\( \frac{9 + 5 + 8 + 6}{4} \) = \( \frac{28}{4} \) = 7
If a rectangle is twice as long as it is wide and has a perimeter of 54 meters, what is the area of the rectangle?
| 18 m2 | |
| 2 m2 | |
| 128 m2 | |
| 162 m2 |
The area of a rectangle is width (w) x height (h). In this problem we know that the rectangle is twice as long as it is wide so h = 2w. The perimeter of a rectangle is 2w + 2h and we know that the perimeter of this rectangle is 54 meters so the equation becomes: 2w + 2h = 54.
Putting these two equations together and solving for width (w):
2w + 2h = 54
w + h = \( \frac{54}{2} \)
w + h = 27
w = 27 - h
From the question we know that h = 2w so substituting 2w for h gives us:
w = 27 - 2w
3w = 27
w = \( \frac{27}{3} \)
w = 9
Since h = 2w that makes h = (2 x 9) = 18 and the area = h x w = 9 x 18 = 162 m2
If \( \left|z + 1\right| \) + 1 = 1, which of these is a possible value for z?
| -19 | |
| 10 | |
| 0 | |
| -1 |
First, solve for \( \left|z + 1\right| \):
\( \left|z + 1\right| \) + 1 = 1
\( \left|z + 1\right| \) = 1 - 1
\( \left|z + 1\right| \) = 0
The value inside the absolute value brackets can be either positive or negative so (z + 1) must equal + 0 or -0 for \( \left|z + 1\right| \) to equal 0:
| z + 1 = 0 z = 0 - 1 z = -1 | z + 1 = 0 z = 0 - 1 z = -1 |
So, z = -1 or z = -1.