ASVAB Arithmetic Reasoning Practice Test 513236 Results

Your Results Global Average
Questions 5 5
Correct 0 3.00
Score 0% 60%

Review

1

What is 3\( \sqrt{9} \) x 5\( \sqrt{6} \)?

41% Answer Correctly
8\( \sqrt{54} \)
15\( \sqrt{6} \)
15\( \sqrt{9} \)
45\( \sqrt{6} \)

Solution

To multiply terms with radicals, multiply the coefficients and radicands separately:

3\( \sqrt{9} \) x 5\( \sqrt{6} \)
(3 x 5)\( \sqrt{9 \times 6} \)
15\( \sqrt{54} \)

Now we need to simplify the radical:

15\( \sqrt{54} \)
15\( \sqrt{6 \times 9} \)
15\( \sqrt{6 \times 3^2} \)
(15)(3)\( \sqrt{6} \)
45\( \sqrt{6} \)


2

What is 2z7 + z7?

66% Answer Correctly
z-7
-z7
3z7
3z49

Solution

To add or subtract terms with exponents, both the base and the exponent must be the same. In this case they are so add the coefficients and retain the base and exponent:

2z7 + 1z7
(2 + 1)z7
3z7


3

53% Answer Correctly
0.2
4.8
1
0.8

Solution


1


4

What is \( \frac{15\sqrt{42}}{3\sqrt{6}} \)?

71% Answer Correctly
\(\frac{1}{7}\) \( \sqrt{\frac{1}{5}} \)
7 \( \sqrt{\frac{1}{5}} \)
\(\frac{1}{5}\) \( \sqrt{7} \)
5 \( \sqrt{7} \)

Solution

To divide terms with radicals, divide the coefficients and radicands separately:

\( \frac{15\sqrt{42}}{3\sqrt{6}} \)
\( \frac{15}{3} \) \( \sqrt{\frac{42}{6}} \)
5 \( \sqrt{7} \)


5

If \(\left|a\right| = 7\), which of the following best describes a?

67% Answer Correctly

a = -7

a = 7 or a = -7

none of these is correct

a = 7


Solution

The absolute value is the positive magnitude of a particular number or variable and is indicated by two vertical lines: \(\left|-5\right| = 5\). In the case of a variable absolute value (\(\left|a\right| = 5\)) the value of a can be either positive or negative (a = -5 or a = 5).