| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.41 |
| Score | 0% | 68% |
What is \( \frac{-9z^9}{4z^4} \)?
| -\(\frac{4}{9}\)z5 | |
| -2\(\frac{1}{4}\)z5 | |
| -2\(\frac{1}{4}\)z\(\frac{4}{9}\) | |
| -2\(\frac{1}{4}\)z36 |
To divide terms with exponents, the base of both exponents must be the same. In this case they are so divide the coefficients and subtract the exponents:
\( \frac{-9z^9}{4z^4} \)
\( \frac{-9}{4} \) z(9 - 4)
-2\(\frac{1}{4}\)z5
A factor is a positive __________ that divides evenly into a given number.
improper fraction |
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mixed number |
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integer |
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fraction |
A factor is a positive integer that divides evenly into a given number. For example, the factors of 8 are 1, 2, 4, and 8.
If all of a roofing company's 16 workers are required to staff 4 roofing crews, how many workers need to be added during the busy season in order to send 8 complete crews out on jobs?
| 18 | |
| 16 | |
| 12 | |
| 10 |
In order to find how many additional workers are needed to staff the extra crews you first need to calculate how many workers are on a crew. There are 16 workers at the company now and that's enough to staff 4 crews so there are \( \frac{16}{4} \) = 4 workers on a crew. 8 crews are needed for the busy season which, at 4 workers per crew, means that the roofing company will need 8 x 4 = 32 total workers to staff the crews during the busy season. The company already employs 16 workers so they need to add 32 - 16 = 16 new staff for the busy season.
17 members of a bridal party need transported to a wedding reception but there are only 3 4-passenger taxis available to take them. How many will need to find other transportation?
| 5 | |
| 7 | |
| 4 | |
| 1 |
There are 3 4-passenger taxis available so that's 3 x 4 = 12 total seats. There are 17 people needing transportation leaving 17 - 12 = 5 who will have to find other transportation.
What is \( \frac{2}{5} \) x \( \frac{3}{9} \)?
| \(\frac{4}{21}\) | |
| \(\frac{1}{24}\) | |
| \(\frac{1}{18}\) | |
| \(\frac{2}{15}\) |
To multiply fractions, multiply the numerators together and then multiply the denominators together:
\( \frac{2}{5} \) x \( \frac{3}{9} \) = \( \frac{2 x 3}{5 x 9} \) = \( \frac{6}{45} \) = \(\frac{2}{15}\)