| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.16 |
| Score | 0% | 63% |
Cooks are needed to prepare for a large party. Each cook can bake either 4 large cakes or 12 small cakes per hour. The kitchen is available for 4 hours and 23 large cakes and 500 small cakes need to be baked.
How many cooks are required to bake the required number of cakes during the time the kitchen is available?
| 13 | |
| 8 | |
| 11 | |
| 14 |
If a single cook can bake 4 large cakes per hour and the kitchen is available for 4 hours, a single cook can bake 4 x 4 = 16 large cakes during that time. 23 large cakes are needed for the party so \( \frac{23}{16} \) = 1\(\frac{7}{16}\) cooks are needed to bake the required number of large cakes.
If a single cook can bake 12 small cakes per hour and the kitchen is available for 4 hours, a single cook can bake 12 x 4 = 48 small cakes during that time. 500 small cakes are needed for the party so \( \frac{500}{48} \) = 10\(\frac{5}{12}\) cooks are needed to bake the required number of small cakes.
Because you can't employ a fractional cook, round the number of cooks needed for each type of cake up to the next whole number resulting in 2 + 11 = 13 cooks.
What is (b2)4?
| b8 | |
| b-2 | |
| 4b2 | |
| b6 |
To raise a term with an exponent to another exponent, retain the base and multiply the exponents:
(b2)4How many hours does it take a car to travel 65 miles at an average speed of 65 miles per hour?
| 1 hour | |
| 5 hours | |
| 2 hours | |
| 9 hours |
Average speed in miles per hour is the number of miles traveled divided by the number of hours:
speed = \( \frac{\text{distance}}{\text{time}} \)Solving for time:
time = \( \frac{\text{distance}}{\text{speed}} \)
time = \( \frac{65mi}{65mph} \)
1 hour
What is 3\( \sqrt{2} \) x 4\( \sqrt{3} \)?
| 12\( \sqrt{5} \) | |
| 12\( \sqrt{6} \) | |
| 12\( \sqrt{3} \) | |
| 7\( \sqrt{6} \) |
To multiply terms with radicals, multiply the coefficients and radicands separately:
3\( \sqrt{2} \) x 4\( \sqrt{3} \)
(3 x 4)\( \sqrt{2 \times 3} \)
12\( \sqrt{6} \)
Monty loaned Latoya $900 at an annual interest rate of 5%. If no payments are made, what is the total amount owed at the end of the first year?
| $927 | |
| $918 | |
| $945 | |
| $972 |
The yearly interest charged on this loan is the annual interest rate multiplied by the amount borrowed:
interest = annual interest rate x loan amount
i = (\( \frac{6}{100} \)) x $900
i = 0.05 x $900
No payments were made so the total amount due is the original amount + the accumulated interest:
total = $900 + $45