| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.32 |
| Score | 0% | 66% |
Cooks are needed to prepare for a large party. Each cook can bake either 2 large cakes or 11 small cakes per hour. The kitchen is available for 4 hours and 23 large cakes and 480 small cakes need to be baked.
How many cooks are required to bake the required number of cakes during the time the kitchen is available?
| 11 | |
| 7 | |
| 14 | |
| 9 |
If a single cook can bake 2 large cakes per hour and the kitchen is available for 4 hours, a single cook can bake 2 x 4 = 8 large cakes during that time. 23 large cakes are needed for the party so \( \frac{23}{8} \) = 2\(\frac{7}{8}\) cooks are needed to bake the required number of large cakes.
If a single cook can bake 11 small cakes per hour and the kitchen is available for 4 hours, a single cook can bake 11 x 4 = 44 small cakes during that time. 480 small cakes are needed for the party so \( \frac{480}{44} \) = 10\(\frac{10}{11}\) cooks are needed to bake the required number of small cakes.
Because you can't employ a fractional cook, round the number of cooks needed for each type of cake up to the next whole number resulting in 3 + 11 = 14 cooks.
What is the next number in this sequence: 1, 3, 5, 7, 9, __________ ?
| 19 | |
| 15 | |
| 13 | |
| 11 |
The equation for this sequence is:
an = an-1 + 2
where n is the term's order in the sequence, an is the value of the term, and an-1 is the value of the term before an. This makes the next number:
a6 = a5 + 2
a6 = 9 + 2
a6 = 11
This property states taht the order of addition or multiplication does not mater. For example, 2 + 5 and 5 + 2 are equivalent.
PEDMAS |
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distributive |
|
associative |
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commutative |
The commutative property states that, when adding or multiplying numbers, the order in which they're added or multiplied does not matter. For example, 3 + 4 and 4 + 3 give the same result, as do 3 x 4 and 4 x 3.
What is (b5)3?
| b2 | |
| b8 | |
| b15 | |
| 3b5 |
To raise a term with an exponent to another exponent, retain the base and multiply the exponents:
(b5)3What is \( \frac{-2z^7}{7z^2} \)?
| -\(\frac{2}{7}\)z14 | |
| -\(\frac{2}{7}\)z9 | |
| -3\(\frac{1}{2}\)z9 | |
| -\(\frac{2}{7}\)z5 |
To divide terms with exponents, the base of both exponents must be the same. In this case they are so divide the coefficients and subtract the exponents:
\( \frac{-2z^7}{7z^2} \)
\( \frac{-2}{7} \) z(7 - 2)
-\(\frac{2}{7}\)z5