ASVAB Arithmetic Reasoning Practice Test 515535 Results

Your Results Global Average
Questions 5 5
Correct 0 3.14
Score 0% 63%

Review

1

52% Answer Correctly
1.0
1
1.2
3.6

Solution


1


2

Solve 2 + (5 + 3) ÷ 4 x 3 - 42

52% Answer Correctly
\(\frac{3}{4}\)
3\(\frac{1}{2}\)
-8
1\(\frac{1}{8}\)

Solution

Use PEMDAS (Parentheses, Exponents, Multipy/Divide, Add/Subtract):

2 + (5 + 3) ÷ 4 x 3 - 42
P: 2 + (8) ÷ 4 x 3 - 42
E: 2 + 8 ÷ 4 x 3 - 16
MD: 2 + \( \frac{8}{4} \) x 3 - 16
MD: 2 + \( \frac{24}{4} \) - 16
AS: \( \frac{8}{4} \) + \( \frac{24}{4} \) - 16
AS: \( \frac{32}{4} \) - 16
AS: \( \frac{32 - 64}{4} \)
\( \frac{-32}{4} \)
-8


3

What is \( \frac{2b^8}{3b^3} \)?

60% Answer Correctly
\(\frac{2}{3}\)b24
\(\frac{2}{3}\)b2\(\frac{2}{3}\)
\(\frac{2}{3}\)b5
\(\frac{2}{3}\)b11

Solution

To divide terms with exponents, the base of both exponents must be the same. In this case they are so divide the coefficients and subtract the exponents:

\( \frac{2b^8}{3b^3} \)
\( \frac{2}{3} \) b(8 - 3)
\(\frac{2}{3}\)b5


4

What is \( \sqrt{\frac{49}{49}} \)?

70% Answer Correctly
3\(\frac{1}{2}\)
\(\frac{1}{3}\)
1
\(\frac{2}{3}\)

Solution

To take the square root of a fraction, break the fraction into two separate roots then calculate the square root of the numerator and denominator separately:

\( \sqrt{\frac{49}{49}} \)
\( \frac{\sqrt{49}}{\sqrt{49}} \)
\( \frac{\sqrt{7^2}}{\sqrt{7^2}} \)
1


5

Which of the following is not an integer?

77% Answer Correctly

1

\({1 \over 2}\)

-1

0


Solution

An integer is any whole number, including zero. An integer can be either positive or negative. Examples include -77, -1, 0, 55, 119.