ASVAB Arithmetic Reasoning Practice Test 520407 Results

Your Results Global Average
Questions 5 5
Correct 0 3.08
Score 0% 62%

Review

1

Convert y-5 to remove the negative exponent.

68% Answer Correctly
\( \frac{5}{y} \)
\( \frac{-1}{-5y} \)
\( \frac{-1}{-5y^{5}} \)
\( \frac{1}{y^5} \)

Solution

To convert a negative exponent to a positive exponent, calculate the positive exponent then take the reciprocal.


2

If a mayor is elected with 55% of the votes cast and 58% of a town's 27,000 voters cast a vote, how many votes did the mayor receive?

49% Answer Correctly
12,215
8,143
8,613
9,396

Solution

If 58% of the town's 27,000 voters cast ballots the number of votes cast is:

(\( \frac{58}{100} \)) x 27,000 = \( \frac{1,566,000}{100} \) = 15,660

The mayor got 55% of the votes cast which is:

(\( \frac{55}{100} \)) x 15,660 = \( \frac{861,300}{100} \) = 8,613 votes.


3

Simplify \( \frac{16}{64} \).

77% Answer Correctly
\( \frac{7}{13} \)
\( \frac{1}{4} \)
\( \frac{2}{3} \)
\( \frac{9}{13} \)

Solution

To simplify this fraction, first find the greatest common factor between them. The factors of 16 are [1, 2, 4, 8, 16] and the factors of 64 are [1, 2, 4, 8, 16, 32, 64]. They share 5 factors [1, 2, 4, 8, 16] making 16 their greatest common factor (GCF).

Next, divide both numerator and denominator by the GCF:

\( \frac{16}{64} \) = \( \frac{\frac{16}{16}}{\frac{64}{16}} \) = \( \frac{1}{4} \)


4

If the ratio of home fans to visiting fans in a crowd is 5:1 and all 42,000 seats in a stadium are filled, how many home fans are in attendance?

50% Answer Correctly
31,500
35,000
39,200
39,167

Solution

A ratio of 5:1 means that there are 5 home fans for every one visiting fan. So, of every 6 fans, 5 are home fans and \( \frac{5}{6} \) of every fan in the stadium is a home fan:

42,000 fans x \( \frac{5}{6} \) = \( \frac{210000}{6} \) = 35,000 fans.


5

If \( \left|x - 8\right| \) - 8 = 3, which of these is a possible value for x?

62% Answer Correctly
3
19
9
-21

Solution

First, solve for \( \left|x - 8\right| \):

\( \left|x - 8\right| \) - 8 = 3
\( \left|x - 8\right| \) = 3 + 8
\( \left|x - 8\right| \) = 11

The value inside the absolute value brackets can be either positive or negative so (x - 8) must equal + 11 or -11 for \( \left|x - 8\right| \) to equal 11:

x - 8 = 11
x = 11 + 8
x = 19
x - 8 = -11
x = -11 + 8
x = -3

So, x = -3 or x = 19.