ASVAB Arithmetic Reasoning Practice Test 525779 Results

Your Results Global Average
Questions 5 5
Correct 0 3.48
Score 0% 70%

Review

1

What is (b3)5?

80% Answer Correctly
b8
5b3
b15
b2

Solution

To raise a term with an exponent to another exponent, retain the base and multiply the exponents:

(b3)5
b(3 * 5)
b15


2

A menswear store is having a sale: "Buy one shirt at full price and get another shirt for 20% off." If Alex buys two shirts, each with a regular price of $32, how much money will he save?

70% Answer Correctly
$6.40
$4.80
$8.00
$1.60

Solution

By buying two shirts, Alex will save $32 x \( \frac{20}{100} \) = \( \frac{$32 x 20}{100} \) = \( \frac{$640}{100} \) = $6.40 on the second shirt.


3

If a car travels 175 miles in 5 hours, what is the average speed?

86% Answer Correctly
35 mph
60 mph
70 mph
45 mph

Solution

Average speed in miles per hour is the number of miles traveled divided by the number of hours:

speed = \( \frac{\text{distance}}{\text{time}} \)
speed = \( \frac{175mi}{5h} \)
35 mph


4

a(b + c) = ab + ac defines which of the following?

74% Answer Correctly

distributive property for division

commutative property for division

commutative property for multiplication

distributive property for multiplication


Solution

The distributive property for multiplication helps in solving expressions like a(b + c). It specifies that the result of multiplying one number by the sum or difference of two numbers can be obtained by multiplying each number individually and then totaling the results: a(b + c) = ab + ac. For example, 4(10-5) = (4 x 10) - (4 x 5) = 40 - 20 = 20.


5

What is \( 3 \)\( \sqrt{48} \) - \( 2 \)\( \sqrt{3} \)

38% Answer Correctly
6\( \sqrt{48} \)
\( \sqrt{16} \)
10\( \sqrt{3} \)
\( \sqrt{-7} \)

Solution

To subtract these radicals together their radicands must be the same:

3\( \sqrt{48} \) - 2\( \sqrt{3} \)
3\( \sqrt{16 \times 3} \) - 2\( \sqrt{3} \)
3\( \sqrt{4^2 \times 3} \) - 2\( \sqrt{3} \)
(3)(4)\( \sqrt{3} \) - 2\( \sqrt{3} \)
12\( \sqrt{3} \) - 2\( \sqrt{3} \)

Now that the radicands are identical, you can subtract them:

12\( \sqrt{3} \) - 2\( \sqrt{3} \)
(12 - 2)\( \sqrt{3} \)
10\( \sqrt{3} \)