ASVAB Arithmetic Reasoning Practice Test 525862 Results

Your Results Global Average
Questions 5 5
Correct 0 2.96
Score 0% 59%

Review

1

What is \( \frac{4}{9} \) x \( \frac{2}{8} \)?

72% Answer Correctly
\(\frac{8}{45}\)
\(\frac{1}{9}\)
\(\frac{9}{40}\)
\(\frac{1}{15}\)

Solution

To multiply fractions, multiply the numerators together and then multiply the denominators together:

\( \frac{4}{9} \) x \( \frac{2}{8} \) = \( \frac{4 x 2}{9 x 8} \) = \( \frac{8}{72} \) = \(\frac{1}{9}\)


2

What is \( \frac{15\sqrt{28}}{5\sqrt{7}} \)?

71% Answer Correctly
\(\frac{1}{4}\) \( \sqrt{3} \)
\(\frac{1}{3}\) \( \sqrt{\frac{1}{4}} \)
3 \( \sqrt{4} \)
4 \( \sqrt{3} \)

Solution

To divide terms with radicals, divide the coefficients and radicands separately:

\( \frac{15\sqrt{28}}{5\sqrt{7}} \)
\( \frac{15}{5} \) \( \sqrt{\frac{28}{7}} \)
3 \( \sqrt{4} \)


3

What is \( 4 \)\( \sqrt{75} \) - \( 9 \)\( \sqrt{3} \)

38% Answer Correctly
11\( \sqrt{3} \)
-5\( \sqrt{75} \)
-5\( \sqrt{225} \)
36\( \sqrt{75} \)

Solution

To subtract these radicals together their radicands must be the same:

4\( \sqrt{75} \) - 9\( \sqrt{3} \)
4\( \sqrt{25 \times 3} \) - 9\( \sqrt{3} \)
4\( \sqrt{5^2 \times 3} \) - 9\( \sqrt{3} \)
(4)(5)\( \sqrt{3} \) - 9\( \sqrt{3} \)
20\( \sqrt{3} \) - 9\( \sqrt{3} \)

Now that the radicands are identical, you can subtract them:

20\( \sqrt{3} \) - 9\( \sqrt{3} \)
(20 - 9)\( \sqrt{3} \)
11\( \sqrt{3} \)


4

A bread recipe calls for 3\(\frac{1}{2}\) cups of flour. If you only have 1\(\frac{1}{8}\) cups, how much more flour is needed?

62% Answer Correctly
2\(\frac{3}{8}\) cups
\(\frac{7}{8}\) cups
3\(\frac{1}{8}\) cups
2\(\frac{1}{8}\) cups

Solution

The amount of flour you need is (3\(\frac{1}{2}\) - 1\(\frac{1}{8}\)) cups. Rewrite the quantities so they share a common denominator and subtract:

(\( \frac{28}{8} \) - \( \frac{9}{8} \)) cups
\( \frac{19}{8} \) cups
2\(\frac{3}{8}\) cups


5

How many 2 gallon cans worth of fuel would you need to pour into an empty 8 gallon tank to fill it exactly halfway?

52% Answer Correctly
9
2
2
4

Solution

To fill a 8 gallon tank exactly halfway you'll need 4 gallons of fuel. Each fuel can holds 2 gallons so:

cans = \( \frac{4 \text{ gallons}}{2 \text{ gallons}} \) = 2