| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.96 |
| Score | 0% | 59% |
What is \( \frac{4}{9} \) x \( \frac{2}{8} \)?
| \(\frac{8}{45}\) | |
| \(\frac{1}{9}\) | |
| \(\frac{9}{40}\) | |
| \(\frac{1}{15}\) |
To multiply fractions, multiply the numerators together and then multiply the denominators together:
\( \frac{4}{9} \) x \( \frac{2}{8} \) = \( \frac{4 x 2}{9 x 8} \) = \( \frac{8}{72} \) = \(\frac{1}{9}\)
What is \( \frac{15\sqrt{28}}{5\sqrt{7}} \)?
| \(\frac{1}{4}\) \( \sqrt{3} \) | |
| \(\frac{1}{3}\) \( \sqrt{\frac{1}{4}} \) | |
| 3 \( \sqrt{4} \) | |
| 4 \( \sqrt{3} \) |
To divide terms with radicals, divide the coefficients and radicands separately:
\( \frac{15\sqrt{28}}{5\sqrt{7}} \)
\( \frac{15}{5} \) \( \sqrt{\frac{28}{7}} \)
3 \( \sqrt{4} \)
What is \( 4 \)\( \sqrt{75} \) - \( 9 \)\( \sqrt{3} \)
| 11\( \sqrt{3} \) | |
| -5\( \sqrt{75} \) | |
| -5\( \sqrt{225} \) | |
| 36\( \sqrt{75} \) |
To subtract these radicals together their radicands must be the same:
4\( \sqrt{75} \) - 9\( \sqrt{3} \)
4\( \sqrt{25 \times 3} \) - 9\( \sqrt{3} \)
4\( \sqrt{5^2 \times 3} \) - 9\( \sqrt{3} \)
(4)(5)\( \sqrt{3} \) - 9\( \sqrt{3} \)
20\( \sqrt{3} \) - 9\( \sqrt{3} \)
Now that the radicands are identical, you can subtract them:
20\( \sqrt{3} \) - 9\( \sqrt{3} \)A bread recipe calls for 3\(\frac{1}{2}\) cups of flour. If you only have 1\(\frac{1}{8}\) cups, how much more flour is needed?
| 2\(\frac{3}{8}\) cups | |
| \(\frac{7}{8}\) cups | |
| 3\(\frac{1}{8}\) cups | |
| 2\(\frac{1}{8}\) cups |
The amount of flour you need is (3\(\frac{1}{2}\) - 1\(\frac{1}{8}\)) cups. Rewrite the quantities so they share a common denominator and subtract:
(\( \frac{28}{8} \) - \( \frac{9}{8} \)) cups
\( \frac{19}{8} \) cups
2\(\frac{3}{8}\) cups
How many 2 gallon cans worth of fuel would you need to pour into an empty 8 gallon tank to fill it exactly halfway?
| 9 | |
| 2 | |
| 2 | |
| 4 |
To fill a 8 gallon tank exactly halfway you'll need 4 gallons of fuel. Each fuel can holds 2 gallons so:
cans = \( \frac{4 \text{ gallons}}{2 \text{ gallons}} \) = 2