ASVAB Arithmetic Reasoning Practice Test 526451 Results

Your Results Global Average
Questions 5 5
Correct 0 3.41
Score 0% 68%

Review

1

What is the next number in this sequence: 1, 4, 7, 10, 13, __________ ?

92% Answer Correctly
20
16
23
13

Solution

The equation for this sequence is:

an = an-1 + 3

where n is the term's order in the sequence, an is the value of the term, and an-1 is the value of the term before an. This makes the next number:

a6 = a5 + 3
a6 = 13 + 3
a6 = 16


2

Which of the following is an improper fraction?

70% Answer Correctly

\({a \over 5} \)

\({2 \over 5} \)

\(1 {2 \over 5} \)

\({7 \over 5} \)


Solution

A rational number (or fraction) is represented as a ratio between two integers, a and b, and has the form \({a \over b}\) where a is the numerator and b is the denominator. An improper fraction (\({5 \over 3} \)) has a numerator with a greater absolute value than the denominator and can be converted into a mixed number (\(1 {2 \over 3} \)) which has a whole number part and a fractional part.


3

What is 6\( \sqrt{5} \) x 9\( \sqrt{3} \)?

41% Answer Correctly
54\( \sqrt{5} \)
54\( \sqrt{15} \)
15\( \sqrt{5} \)
15\( \sqrt{15} \)

Solution

To multiply terms with radicals, multiply the coefficients and radicands separately:

6\( \sqrt{5} \) x 9\( \sqrt{3} \)
(6 x 9)\( \sqrt{5 \times 3} \)
54\( \sqrt{15} \)


4

Simplify \( \frac{20}{60} \).

77% Answer Correctly
\( \frac{5}{8} \)
\( \frac{7}{20} \)
\( \frac{5}{7} \)
\( \frac{1}{3} \)

Solution

To simplify this fraction, first find the greatest common factor between them. The factors of 20 are [1, 2, 4, 5, 10, 20] and the factors of 60 are [1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30, 60]. They share 6 factors [1, 2, 4, 5, 10, 20] making 20 their greatest common factor (GCF).

Next, divide both numerator and denominator by the GCF:

\( \frac{20}{60} \) = \( \frac{\frac{20}{20}}{\frac{60}{20}} \) = \( \frac{1}{3} \)


5

If \( \left|c + 4\right| \) + 7 = -5, which of these is a possible value for c?

62% Answer Correctly
9
8
4
6

Solution

First, solve for \( \left|c + 4\right| \):

\( \left|c + 4\right| \) + 7 = -5
\( \left|c + 4\right| \) = -5 - 7
\( \left|c + 4\right| \) = -12

The value inside the absolute value brackets can be either positive or negative so (c + 4) must equal - 12 or --12 for \( \left|c + 4\right| \) to equal -12:

c + 4 = -12
c = -12 - 4
c = -16
c + 4 = 12
c = 12 - 4
c = 8

So, c = 8 or c = -16.