| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.41 |
| Score | 0% | 68% |
What is the next number in this sequence: 1, 4, 7, 10, 13, __________ ?
| 20 | |
| 16 | |
| 23 | |
| 13 |
The equation for this sequence is:
an = an-1 + 3
where n is the term's order in the sequence, an is the value of the term, and an-1 is the value of the term before an. This makes the next number:
a6 = a5 + 3
a6 = 13 + 3
a6 = 16
Which of the following is an improper fraction?
\({a \over 5} \) |
|
\({2 \over 5} \) |
|
\(1 {2 \over 5} \) |
|
\({7 \over 5} \) |
A rational number (or fraction) is represented as a ratio between two integers, a and b, and has the form \({a \over b}\) where a is the numerator and b is the denominator. An improper fraction (\({5 \over 3} \)) has a numerator with a greater absolute value than the denominator and can be converted into a mixed number (\(1 {2 \over 3} \)) which has a whole number part and a fractional part.
What is 6\( \sqrt{5} \) x 9\( \sqrt{3} \)?
| 54\( \sqrt{5} \) | |
| 54\( \sqrt{15} \) | |
| 15\( \sqrt{5} \) | |
| 15\( \sqrt{15} \) |
To multiply terms with radicals, multiply the coefficients and radicands separately:
6\( \sqrt{5} \) x 9\( \sqrt{3} \)
(6 x 9)\( \sqrt{5 \times 3} \)
54\( \sqrt{15} \)
Simplify \( \frac{20}{60} \).
| \( \frac{5}{8} \) | |
| \( \frac{7}{20} \) | |
| \( \frac{5}{7} \) | |
| \( \frac{1}{3} \) |
To simplify this fraction, first find the greatest common factor between them. The factors of 20 are [1, 2, 4, 5, 10, 20] and the factors of 60 are [1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30, 60]. They share 6 factors [1, 2, 4, 5, 10, 20] making 20 their greatest common factor (GCF).
Next, divide both numerator and denominator by the GCF:
\( \frac{20}{60} \) = \( \frac{\frac{20}{20}}{\frac{60}{20}} \) = \( \frac{1}{3} \)
If \( \left|c + 4\right| \) + 7 = -5, which of these is a possible value for c?
| 9 | |
| 8 | |
| 4 | |
| 6 |
First, solve for \( \left|c + 4\right| \):
\( \left|c + 4\right| \) + 7 = -5
\( \left|c + 4\right| \) = -5 - 7
\( \left|c + 4\right| \) = -12
The value inside the absolute value brackets can be either positive or negative so (c + 4) must equal - 12 or --12 for \( \left|c + 4\right| \) to equal -12:
| c + 4 = -12 c = -12 - 4 c = -16 | c + 4 = 12 c = 12 - 4 c = 8 |
So, c = 8 or c = -16.