| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.23 |
| Score | 0% | 65% |
A menswear store is having a sale: "Buy one shirt at full price and get another shirt for 5% off." If Ezra buys two shirts, each with a regular price of $25, how much will he pay for both shirts?
| $23.75 | |
| $1.25 | |
| $30.00 | |
| $48.75 |
By buying two shirts, Ezra will save $25 x \( \frac{5}{100} \) = \( \frac{$25 x 5}{100} \) = \( \frac{$125}{100} \) = $1.25 on the second shirt.
So, his total cost will be
$25.00 + ($25.00 - $1.25)
$25.00 + $23.75
$48.75
What is \( \frac{2}{9} \) ÷ \( \frac{4}{7} \)?
| 1\(\frac{5}{9}\) | |
| \(\frac{8}{35}\) | |
| \(\frac{7}{18}\) | |
| \(\frac{2}{9}\) |
To divide fractions, invert the second fraction and then multiply:
\( \frac{2}{9} \) ÷ \( \frac{4}{7} \) = \( \frac{2}{9} \) x \( \frac{7}{4} \)
To multiply fractions, multiply the numerators together and then multiply the denominators together:
\( \frac{2}{9} \) x \( \frac{7}{4} \) = \( \frac{2 x 7}{9 x 4} \) = \( \frac{14}{36} \) = \(\frac{7}{18}\)
What is \( \frac{4}{6} \) x \( \frac{3}{8} \)?
| \(\frac{1}{4}\) | |
| \(\frac{1}{10}\) | |
| \(\frac{3}{35}\) | |
| 2 |
To multiply fractions, multiply the numerators together and then multiply the denominators together:
\( \frac{4}{6} \) x \( \frac{3}{8} \) = \( \frac{4 x 3}{6 x 8} \) = \( \frac{12}{48} \) = \(\frac{1}{4}\)
The total water usage for a city is 35,000 gallons each day. Of that total, 10% is for personal use and 20% is for industrial use. How many more gallons of water each day is consumed for industrial use over personal use?
| 8,550 | |
| 3,200 | |
| 3,500 | |
| 10,000 |
20% of the water consumption is industrial use and 10% is personal use so (20% - 10%) = 10% more water is used for industrial purposes. 35,000 gallons are consumed daily so industry consumes \( \frac{10}{100} \) x 35,000 gallons = 3,500 gallons.
Solve for \( \frac{5!}{6!} \)
| \( \frac{1}{6} \) | |
| 60480 | |
| \( \frac{1}{72} \) | |
| \( \frac{1}{8} \) |
A factorial is the product of an integer and all the positive integers below it. To solve a fraction featuring factorials, expand the factorials and cancel out like numbers:
\( \frac{5!}{6!} \)
\( \frac{5 \times 4 \times 3 \times 2 \times 1}{6 \times 5 \times 4 \times 3 \times 2 \times 1} \)
\( \frac{1}{6} \)
\( \frac{1}{6} \)