ASVAB Arithmetic Reasoning Practice Test 530923 Results

	Your Results	Global Average
Questions	5	5
Correct	0	3.46
Score	0%	69%

Review

What is $ \frac{3}{7} $ ÷ $ \frac{1}{5} $?

68% Answer Correctly

	$\frac{1}{63}$
	15
	$\frac{2}{21}$
	2$\frac{1}{7}$

Solution

To divide fractions, invert the second fraction and then multiply:

$ \frac{3}{7} $ ÷ $ \frac{1}{5} $ = $ \frac{3}{7} $ x $ \frac{5}{1} $

To multiply fractions, multiply the numerators together and then multiply the denominators together:

$ \frac{3}{7} $ x $ \frac{5}{1} $ = $ \frac{3 x 5}{7 x 1} $ = $ \frac{15}{7} $ = 2$\frac{1}{7}$

What is $ \frac{6\sqrt{18}}{3\sqrt{6}} $?

71% Answer Correctly

	2 $ \sqrt{3} $
	$\frac{1}{3}$ $ \sqrt{2} $
	$\frac{1}{2}$ $ \sqrt{\frac{1}{3}} $
	$\frac{1}{2}$ $ \sqrt{3} $

Solution

To divide terms with radicals, divide the coefficients and radicands separately:

$ \frac{6\sqrt{18}}{3\sqrt{6}} $
$ \frac{6}{3} $ $ \sqrt{\frac{18}{6}} $
2 $ \sqrt{3} $

A bread recipe calls for 2$\frac{5}{8}$ cups of flour. If you only have $\frac{1}{2}$ cup, how much more flour is needed?

62% Answer Correctly

	2$\frac{5}{8}$ cups
	3$\frac{1}{8}$ cups
	1$\frac{3}{4}$ cups
	2$\frac{1}{8}$ cups

Solution

The amount of flour you need is (2$\frac{5}{8}$ - $\frac{1}{2}$) cups. Rewrite the quantities so they share a common denominator and subtract:

($ \frac{21}{8} $ - $ \frac{4}{8} $) cups
$ \frac{17}{8} $ cups
2$\frac{1}{8}$ cups

Roger loaned Latoya $1,000 at an annual interest rate of 9%. If no payments are made, what is the total amount owed at the end of the first year?

71% Answer Correctly

	$1,030
	$1,090
	$1,050
	$1,010

Solution

The yearly interest charged on this loan is the annual interest rate multiplied by the amount borrowed:

interest = annual interest rate x loan amount

i = ($ \frac{6}{100} $) x $1,000
i = 0.09 x $1,000

No payments were made so the total amount due is the original amount + the accumulated interest:

total = $1,000 + $90
total = $1,090

Damon loaned Monty $900 at an annual interest rate of 6%. If no payments are made, what is the interest owed on this loan at the end of the first year?

74% Answer Correctly

	$90
	$12
	$54
	$56

Solution

The yearly interest charged on this loan is the annual interest rate multiplied by the amount borrowed:

interest = annual interest rate x loan amount

i = ($ \frac{6}{100} $) x $900
i = 0.06 x $900
i = $54

	\(\frac{1}{63}\)
	15
	\(\frac{2}{21}\)
	2\(\frac{1}{7}\)

	2 \( \sqrt{3} \)
	\(\frac{1}{3}\) \( \sqrt{2} \)
	\(\frac{1}{2}\) \( \sqrt{\frac{1}{3}} \)
	\(\frac{1}{2}\) \( \sqrt{3} \)

	2\(\frac{5}{8}\) cups
	3\(\frac{1}{8}\) cups
	1\(\frac{3}{4}\) cups
	2\(\frac{1}{8}\) cups