ASVAB Arithmetic Reasoning Practice Test 533455 Results

Your Results Global Average
Questions 5 5
Correct 0 3.33
Score 0% 67%

Review

1

Alex loaned Roger $600 at an annual interest rate of 9%. If no payments are made, what is the interest owed on this loan at the end of the first year?

74% Answer Correctly
$54
$84
$108
$36

Solution

The yearly interest charged on this loan is the annual interest rate multiplied by the amount borrowed:

interest = annual interest rate x loan amount

i = (\( \frac{6}{100} \)) x $600
i = 0.09 x $600
i = $54


2

What is the next number in this sequence: 1, 5, 9, 13, 17, __________ ?

92% Answer Correctly
16
22
21
28

Solution

The equation for this sequence is:

an = an-1 + 4

where n is the term's order in the sequence, an is the value of the term, and an-1 is the value of the term before an. This makes the next number:

a6 = a5 + 4
a6 = 17 + 4
a6 = 21


3

Solve for \( \frac{3!}{5!} \)

67% Answer Correctly
\( \frac{1}{20} \)
6
210
\( \frac{1}{3024} \)

Solution

A factorial is the product of an integer and all the positive integers below it. To solve a fraction featuring factorials, expand the factorials and cancel out like numbers:

\( \frac{3!}{5!} \)
\( \frac{3 \times 2 \times 1}{5 \times 4 \times 3 \times 2 \times 1} \)
\( \frac{1}{5 \times 4} \)
\( \frac{1}{20} \)


4

If a mayor is elected with 54% of the votes cast and 79% of a town's 18,000 voters cast a vote, how many votes did the mayor receive?

49% Answer Correctly
7,679
10,523
12,229
10,381

Solution

If 79% of the town's 18,000 voters cast ballots the number of votes cast is:

(\( \frac{79}{100} \)) x 18,000 = \( \frac{1,422,000}{100} \) = 14,220

The mayor got 54% of the votes cast which is:

(\( \frac{54}{100} \)) x 14,220 = \( \frac{767,880}{100} \) = 7,679 votes.


5

How many 2\(\frac{1}{2}\) gallon cans worth of fuel would you need to pour into an empty 15 gallon tank to fill it exactly halfway?

52% Answer Correctly
2
3
8
7

Solution

To fill a 15 gallon tank exactly halfway you'll need 7\(\frac{1}{2}\) gallons of fuel. Each fuel can holds 2\(\frac{1}{2}\) gallons so:

cans = \( \frac{7\frac{1}{2} \text{ gallons}}{2\frac{1}{2} \text{ gallons}} \) = 3