| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.62 |
| Score | 0% | 52% |
A bread recipe calls for 3\(\frac{3}{8}\) cups of flour. If you only have \(\frac{3}{8}\) cup, how much more flour is needed?
| 3 cups | |
| 2\(\frac{3}{4}\) cups | |
| 1\(\frac{3}{4}\) cups | |
| 2\(\frac{1}{8}\) cups |
The amount of flour you need is (3\(\frac{3}{8}\) - \(\frac{3}{8}\)) cups. Rewrite the quantities so they share a common denominator and subtract:
(\( \frac{27}{8} \) - \( \frac{3}{8} \)) cups
\( \frac{24}{8} \) cups
3 cups
What is \( \frac{4}{6} \) - \( \frac{2}{12} \)?
| 2 \( \frac{7}{12} \) | |
| \( \frac{2}{9} \) | |
| \(\frac{1}{2}\) | |
| 2 \( \frac{8}{14} \) |
To subtract these fractions, first find the lowest common multiple of their denominators. The first few multiples of 6 are [6, 12, 18, 24, 30, 36, 42, 48, 54, 60] and the first few multiples of 12 are [12, 24, 36, 48, 60, 72, 84, 96]. The first few multiples they share are [12, 24, 36, 48, 60] making 12 the smallest multiple 6 and 12 share.
Next, convert the fractions so each denominator equals the lowest common multiple:
\( \frac{4 x 2}{6 x 2} \) - \( \frac{2 x 1}{12 x 1} \)
\( \frac{8}{12} \) - \( \frac{2}{12} \)
Now, because the fractions share a common denominator, you can subtract them:
\( \frac{8 - 2}{12} \) = \( \frac{6}{12} \) = \(\frac{1}{2}\)
A circular logo is enlarged to fit the lid of a jar. The new diameter is 60% larger than the original. By what percentage has the area of the logo increased?
| 37\(\frac{1}{2}\)% | |
| 25% | |
| 30% | |
| 32\(\frac{1}{2}\)% |
The area of a circle is given by the formula A = πr2 where r is the radius of the circle. The radius of a circle is its diameter divided by two so A = π(\( \frac{d}{2} \))2. If the diameter of the logo increases by 60% the radius (and, consequently, the total area) increases by \( \frac{60\text{%}}{2} \) = 30%
Which of the following statements about exponents is false?
b1 = b |
|
b0 = 1 |
|
all of these are false |
|
b1 = 1 |
A number with an exponent (be) consists of a base (b) raised to a power (e). The exponent indicates the number of times that the base is multiplied by itself. A base with an exponent of 1 equals the base (b1 = b) and a base with an exponent of 0 equals 1 ( (b0 = 1).
What is 2\( \sqrt{9} \) x 5\( \sqrt{6} \)?
| 7\( \sqrt{9} \) | |
| 7\( \sqrt{6} \) | |
| 10\( \sqrt{15} \) | |
| 30\( \sqrt{6} \) |
To multiply terms with radicals, multiply the coefficients and radicands separately:
2\( \sqrt{9} \) x 5\( \sqrt{6} \)
(2 x 5)\( \sqrt{9 \times 6} \)
10\( \sqrt{54} \)
Now we need to simplify the radical:
10\( \sqrt{54} \)
10\( \sqrt{6 \times 9} \)
10\( \sqrt{6 \times 3^2} \)
(10)(3)\( \sqrt{6} \)
30\( \sqrt{6} \)