| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.97 |
| Score | 0% | 59% |
The __________ is the greatest factor that divides two integers.
absolute value |
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greatest common factor |
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greatest common multiple |
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least common multiple |
The greatest common factor (GCF) is the greatest factor that divides two integers.
What is -7c3 - 7c3?
| 9 | |
| -14c3 | |
| 14c3 | |
| 14c-3 |
To add or subtract terms with exponents, both the base and the exponent must be the same. In this case they are so subtract the coefficients and retain the base and exponent:
-7c3 - 7c3
(-7 - 7)c3
-14c3
What is \( 7 \)\( \sqrt{80} \) - \( 4 \)\( \sqrt{5} \)
| 24\( \sqrt{5} \) | |
| 3\( \sqrt{400} \) | |
| 3\( \sqrt{16} \) | |
| 28\( \sqrt{5} \) |
To subtract these radicals together their radicands must be the same:
7\( \sqrt{80} \) - 4\( \sqrt{5} \)
7\( \sqrt{16 \times 5} \) - 4\( \sqrt{5} \)
7\( \sqrt{4^2 \times 5} \) - 4\( \sqrt{5} \)
(7)(4)\( \sqrt{5} \) - 4\( \sqrt{5} \)
28\( \sqrt{5} \) - 4\( \sqrt{5} \)
Now that the radicands are identical, you can subtract them:
28\( \sqrt{5} \) - 4\( \sqrt{5} \)On average, the center for a basketball team hits 45% of his shots while a guard on the same team hits 50% of his shots. If the guard takes 10 shots during a game, how many shots will the center have to take to score as many points as the guard assuming each shot is worth the same number of points?
| 25 | |
| 11 | |
| 13 | |
| 21 |
guard shots made = shots taken x \( \frac{\text{% made}}{100} \) = 10 x \( \frac{50}{100} \) = \( \frac{50 x 10}{100} \) = \( \frac{500}{100} \) = 5 shots
The center makes 45% of his shots so he'll have to take:
shots made = shots taken x \( \frac{\text{% made}}{100} \)
shots taken = \( \frac{\text{shots taken}}{\frac{\text{% made}}{100}} \)
to make as many shots as the guard. Plugging in values for the center gives us:
center shots taken = \( \frac{5}{\frac{45}{100}} \) = 5 x \( \frac{100}{45} \) = \( \frac{5 x 100}{45} \) = \( \frac{500}{45} \) = 11 shots
to make the same number of shots as the guard and thus score the same number of points.
8 members of a bridal party need transported to a wedding reception but there are only 3 2-passenger taxis available to take them. How many will need to find other transportation?
| 6 | |
| 2 | |
| 8 | |
| 3 |
There are 3 2-passenger taxis available so that's 3 x 2 = 6 total seats. There are 8 people needing transportation leaving 8 - 6 = 2 who will have to find other transportation.