ASVAB Arithmetic Reasoning Practice Test 548128 Results

Your Results Global Average
Questions 5 5
Correct 0 3.27
Score 0% 65%

Review

1

Which of the following is not a prime number?

65% Answer Correctly

5

2

9

7


Solution

A prime number is an integer greater than 1 that has no factors other than 1 and itself. Examples of prime numbers include 2, 3, 5, 7, and 11.


2

What is \( \frac{7}{9} \) + \( \frac{5}{15} \)?

59% Answer Correctly
1\(\frac{1}{9}\)
1 \( \frac{8}{45} \)
1 \( \frac{1}{45} \)
2 \( \frac{9}{45} \)

Solution

To add these fractions, first find the lowest common multiple of their denominators. The first few multiples of 9 are [9, 18, 27, 36, 45, 54, 63, 72, 81, 90] and the first few multiples of 15 are [15, 30, 45, 60, 75, 90]. The first few multiples they share are [45, 90] making 45 the smallest multiple 9 and 15 share.

Next, convert the fractions so each denominator equals the lowest common multiple:

\( \frac{7 x 5}{9 x 5} \) + \( \frac{5 x 3}{15 x 3} \)

\( \frac{35}{45} \) + \( \frac{15}{45} \)

Now, because the fractions share a common denominator, you can add them:

\( \frac{35 + 15}{45} \) = \( \frac{50}{45} \) = 1\(\frac{1}{9}\)


3

What is \( \frac{2}{9} \) ÷ \( \frac{4}{6} \)?

68% Answer Correctly
\(\frac{1}{3}\)
\(\frac{16}{35}\)
\(\frac{2}{27}\)
1\(\frac{1}{3}\)

Solution

To divide fractions, invert the second fraction and then multiply:

\( \frac{2}{9} \) ÷ \( \frac{4}{6} \) = \( \frac{2}{9} \) x \( \frac{6}{4} \)

To multiply fractions, multiply the numerators together and then multiply the denominators together:

\( \frac{2}{9} \) x \( \frac{6}{4} \) = \( \frac{2 x 6}{9 x 4} \) = \( \frac{12}{36} \) = \(\frac{1}{3}\)


4

What is the least common multiple of 9 and 15?

72% Answer Correctly
82
45
75
11

Solution

The first few multiples of 9 are [9, 18, 27, 36, 45, 54, 63, 72, 81, 90] and the first few multiples of 15 are [15, 30, 45, 60, 75, 90]. The first few multiples they share are [45, 90] making 45 the smallest multiple 9 and 15 have in common.


5

In a class of 35 students, 14 are taking German and 11 are taking Spanish. Of the students studying German or Spanish, 3 are taking both courses. How many students are not enrolled in either course?

63% Answer Correctly
13
19
17
12

Solution

The number of students taking German or Spanish is 14 + 11 = 25. Of that group of 25, 3 are taking both languages so they've been counted twice (once in the German group and once in the Spanish group). Subtracting them out leaves 25 - 3 = 22 who are taking at least one language. 35 - 22 = 13 students who are not taking either language.