ASVAB Arithmetic Reasoning Practice Test 548495 Results

Your Results Global Average
Questions 5 5
Correct 0 3.23
Score 0% 65%

Review

1

Frank loaned Damon $200 at an annual interest rate of 7%. If no payments are made, what is the interest owed on this loan at the end of the first year?

74% Answer Correctly
$27
$36
$40
$14

Solution

The yearly interest charged on this loan is the annual interest rate multiplied by the amount borrowed:

interest = annual interest rate x loan amount

i = (\( \frac{6}{100} \)) x $200
i = 0.07 x $200
i = $14


2

a(b + c) = ab + ac defines which of the following?

74% Answer Correctly

distributive property for multiplication

distributive property for division

commutative property for multiplication

commutative property for division


Solution

The distributive property for multiplication helps in solving expressions like a(b + c). It specifies that the result of multiplying one number by the sum or difference of two numbers can be obtained by multiplying each number individually and then totaling the results: a(b + c) = ab + ac. For example, 4(10-5) = (4 x 10) - (4 x 5) = 40 - 20 = 20.


3

Which of these numbers is a factor of 56?

69% Answer Correctly
60
14
17
9

Solution

The factors of a number are all positive integers that divide evenly into the number. The factors of 56 are 1, 2, 4, 7, 8, 14, 28, 56.


4

Which of the following is an improper fraction?

70% Answer Correctly

\({2 \over 5} \)

\({7 \over 5} \)

\({a \over 5} \)

\(1 {2 \over 5} \)


Solution

A rational number (or fraction) is represented as a ratio between two integers, a and b, and has the form \({a \over b}\) where a is the numerator and b is the denominator. An improper fraction (\({5 \over 3} \)) has a numerator with a greater absolute value than the denominator and can be converted into a mixed number (\(1 {2 \over 3} \)) which has a whole number part and a fractional part.


5

What is \( 3 \)\( \sqrt{27} \) + \( 3 \)\( \sqrt{3} \)

35% Answer Correctly
6\( \sqrt{9} \)
12\( \sqrt{3} \)
9\( \sqrt{3} \)
6\( \sqrt{3} \)

Solution

To add these radicals together their radicands must be the same:

3\( \sqrt{27} \) + 3\( \sqrt{3} \)
3\( \sqrt{9 \times 3} \) + 3\( \sqrt{3} \)
3\( \sqrt{3^2 \times 3} \) + 3\( \sqrt{3} \)
(3)(3)\( \sqrt{3} \) + 3\( \sqrt{3} \)
9\( \sqrt{3} \) + 3\( \sqrt{3} \)

Now that the radicands are identical, you can add them together:

9\( \sqrt{3} \) + 3\( \sqrt{3} \)
(9 + 3)\( \sqrt{3} \)
12\( \sqrt{3} \)